Edexcel M3 — Question 1 3 marks

Exam BoardEdexcel
ModuleM3 (Mechanics 3)
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircular Motion 1
DifficultyEasy -1.2 This is a straightforward application of the circular motion formula F = mω²r, requiring only algebraic rearrangement to find r. It's a single-step problem with standard values and no conceptual challenges, making it easier than average for A-level.
Spec6.05b Circular motion: v=r*omega and a=v^2/r

A particle of mass \(0.6\) kg moves in a horizontal circle with constant angular speed \(1.5\) radians per second. If the force directed towards the centre of the circle has magnitude \(0.27\) N, find the radius of the circular path. [3 marks]

AnswerMarks Guidance
\(0.27 = mr\omega^2 = 0.6r(1-5^2)\)M1 A1 A1
\(r = 0.2\) m 3 marks
$0.27 = mr\omega^2 = 0.6r(1-5^2)$ | M1 A1 A1 | 
$r = 0.2$ m | | 3 marks
A particle of mass $0.6$ kg moves in a horizontal circle with constant angular speed $1.5$ radians per second. If the force directed towards the centre of the circle has magnitude $0.27$ N, find the radius of the circular path. [3 marks]

\hfill \mbox{\textit{Edexcel M3  Q1 [3]}}