OCR M2 2010 June — Question 1 6 marks

Exam BoardOCR
ModuleM2 (Mechanics 2)
Year2010
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProjectiles
TypeHorizontal projection from height
DifficultyModerate -0.8 This is a straightforward projectile motion problem requiring standard SUVAT equations in two dimensions. Students apply v² = u² + 2as vertically to find the vertical component, then use Pythagoras and trigonometry to find speed and direction. It's routine mechanics with no problem-solving insight required, making it easier than average but not trivial due to the two-dimensional aspect.
Spec3.02h Motion under gravity: vector form3.02i Projectile motion: constant acceleration model

A particle is projected horizontally with a speed of \(7 \text{ ms}^{-1}\) from a point 10 m above horizontal ground. The particle moves freely under gravity. Calculate the speed and direction of motion of the particle at the instant it hits the ground. [6]

A particle is projected horizontally with a speed of $7 \text{ ms}^{-1}$ from a point 10 m above horizontal ground. The particle moves freely under gravity. Calculate the speed and direction of motion of the particle at the instant it hits the ground. [6]

\hfill \mbox{\textit{OCR M2 2010 Q1 [6]}}