| Exam Board | OCR |
|---|---|
| Module | M2 (Mechanics 2) |
| Year | 2013 |
| Session | January |
| Marks | 5 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Work done and energy |
| Difficulty | Easy -1.2 This is a straightforward application of standard work and power formulas (W = Fs cos θ and P = W/t) with no problem-solving required. The constant speed simplifies the mechanics, and all values are given directly. This is easier than average, requiring only routine recall and substitution into memorized formulas. |
| Spec | 6.02a Work done: concept and definition6.02b Calculate work: constant force, resolved component6.02k Power: rate of doing work6.02l Power and velocity: P = Fv |
A block is being pushed in a straight line along horizontal ground by a force of 18 N inclined at 15° below the horizontal. The block moves a distance of 6 m in 5 s with constant speed. Find
\begin{enumerate}[label=(\roman*)]
\item the work done by the force, [3]
\item the power with which the force is working. [2]
\end{enumerate}
\hfill \mbox{\textit{OCR M2 2013 Q1 [5]}}