OCR M2 — Question 2 6 marks

Exam BoardOCR
ModuleM2 (Mechanics 2)
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProjectiles
TypeHorizontal projection from height
DifficultyModerate -0.5 This is a standard projectile motion problem requiring straightforward application of SUVAT equations in two dimensions. Students need to find vertical velocity using v² = u² + 2as, then combine with horizontal velocity using Pythagoras and trigonometry. While it involves multiple steps, it's a routine textbook exercise with no conceptual challenges beyond basic mechanics.
Spec3.02h Motion under gravity: vector form3.02i Projectile motion: constant acceleration model

A particle is projected horizontally with a speed of 6 m s\(^{-1}\) from a point 10 m above horizontal ground. The particle moves freely under gravity. Calculate the speed and direction of motion of the particle at the instant it hits the ground. [6]

A particle is projected horizontally with a speed of 6 m s$^{-1}$ from a point 10 m above horizontal ground. The particle moves freely under gravity. Calculate the speed and direction of motion of the particle at the instant it hits the ground. [6]

\hfill \mbox{\textit{OCR M2  Q2 [6]}}