Edexcel M2 — Question 1 5 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVariable acceleration (1D)
TypeAcceleration from velocity differentiation
DifficultyModerate -0.8 This is a straightforward differentiation problem requiring students to find acceleration by differentiating the velocity function and solving a simple equation. The calculus is routine (power rule only), and solving 2 - 16/t³ = 0 is algebraically simple. Below average difficulty as it's a standard single-concept question with no problem-solving insight required.
Spec1.07b Gradient as rate of change: dy/dx notation3.02f Non-uniform acceleration: using differentiation and integration

A particle \(P\) moves in a straight line so that its velocity \(v\) ms\(^{-1}\) at time \(t\) seconds is given, for \(t > 1\), by the formula \(v = 2t + \frac{8}{t^2}\). Find the time when the acceleration of \(P\) is zero. [5 marks]

AnswerMarks Guidance
\(a = 2 - 16t^3 = 0\) when \(t^3 = 8\)M1 A1 M1 A1 A1 \(t = 2\) (5 marks)
$a = 2 - 16t^3 = 0$ when $t^3 = 8$ | M1 A1 M1 A1 A1 | $t = 2$ (5 marks)
A particle $P$ moves in a straight line so that its velocity $v$ ms$^{-1}$ at time $t$ seconds is given, for $t > 1$, by the formula $v = 2t + \frac{8}{t^2}$. Find the time when the acceleration of $P$ is zero. [5 marks]

\hfill \mbox{\textit{Edexcel M2  Q1 [5]}}