Edexcel M2 — Question 1 4 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicWork done and energy
DifficultyModerate -0.8 This is a straightforward work-energy question requiring only basic understanding that constant speed means zero net work, and applying W = Fs with friction force F = μR. The calculation involves simple unit conversions and multiplication, making it easier than average with no problem-solving insight needed.
Spec3.03r Friction: concept and vector form6.02b Calculate work: constant force, resolved component
A constant force acts on a particle of mass 200 grams, moving it 50 cm in a straight line on a rough horizontal surface at a constant speed. The coefficient of friction between the particle and the surface is \(\frac{1}{4}\). Calculate, in J, the work done by the force. [4 marks]
AnswerMarks
\(F = \frac{1}{4}(0.2g) = 0.49 \text{ N}\)M1 A1 M1 A1
\(W = Fd = 0.49 \times 0.5 = 0.245 \text{ J}\)
Total: 4 marks
$F = \frac{1}{4}(0.2g) = 0.49 \text{ N}$ | M1 A1 M1 A1 | 
$W = Fd = 0.49 \times 0.5 = 0.245 \text{ J}$ | | 
**Total: 4 marks**

---
A constant force acts on a particle of mass 200 grams, moving it 50 cm in a straight line on a rough horizontal surface at a constant speed. The coefficient of friction between the particle and the surface is $\frac{1}{4}$.

Calculate, in J, the work done by the force. [4 marks]

\hfill \mbox{\textit{Edexcel M2  Q1 [4]}}
This paper (8 questions)
View full paper
Q1 4 Q2 5 Q3 8 Q4 9 Q5 10 Q6 12 Q7 12 Q8 15