Edexcel M1 — Question 2 9 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCentre of Mass 1
TypeParticles at coordinate positions
DifficultyModerate -0.3 This is a straightforward M1 statics problem involving moments and equilibrium. Part (a) tests standard modelling assumptions (uniform rod, particle), while parts (b) and (c) require basic moment calculations about a point. The setup is clear, the mathematics is routine (taking moments, solving linear equations), and it's a typical textbook-style question with no novel insight required. Slightly easier than average due to its structured nature and standard techniques.
Spec3.04a Calculate moments: about a point3.04b Equilibrium: zero resultant moment and force6.04c Composite bodies: centre of mass

\includegraphics{figure_1} Figure 1 shows a plank \(AB\) of mass 40 kg and length 6 m, which rests on supports at each of its ends. The plank is wedge-shaped, being thicker at end \(A\) than at end \(B\). A woman of mass 60 kg stands on the plank at a distance of 2 m from \(B\).
  1. Suggest suitable modelling assumptions which can be made about
    1. the plank,
    2. the woman. [3 marks]
    Given that the reactions at each support are of equal magnitude,
  2. find the magnitude of the reaction on the support at \(A\), [2 marks]
  3. calculate the distance of the centre of mass of the plank from \(A\). [4 marks]

AnswerMarks Guidance
(a) (i) non-uniform rodB2
(ii) particleB1
(b) \(\text{resolve } \uparrow: 2R = 40g + 60g = 100g \therefore R = 50g\)M1 A1
(c) \(\text{moments about } A: 40g(x) + 60g(4) - 50g(6) = 0\)M1 A1
\(40gx = 300g - 240g = 60g \therefore x = 1.5 \text{ hence, c.o.m is } 1.5 \text{ m from } A\)M1 A1 (9 marks)
(a) (i) non-uniform rod | B2 |

(ii) particle | B1 |

(b) $\text{resolve } \uparrow: 2R = 40g + 60g = 100g \therefore R = 50g$ | M1 A1 |

(c) $\text{moments about } A: 40g(x) + 60g(4) - 50g(6) = 0$ | M1 A1 |

$40gx = 300g - 240g = 60g \therefore x = 1.5 \text{ hence, c.o.m is } 1.5 \text{ m from } A$ | M1 A1 | (9 marks)
\includegraphics{figure_1}

Figure 1 shows a plank $AB$ of mass 40 kg and length 6 m, which rests on supports at each of its ends. The plank is wedge-shaped, being thicker at end $A$ than at end $B$.

A woman of mass 60 kg stands on the plank at a distance of 2 m from $B$.

\begin{enumerate}[label=(\alph*)]
\item Suggest suitable modelling assumptions which can be made about
\begin{enumerate}[label=(\roman*)]
\item the plank,
\item the woman. [3 marks]
\end{enumerate}

Given that the reactions at each support are of equal magnitude,

\item find the magnitude of the reaction on the support at $A$, [2 marks]
\item calculate the distance of the centre of mass of the plank from $A$. [4 marks]
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1  Q2 [9]}}