Edexcel M1 — Question 5 13 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPulley systems
TypeMulti-stage motion: changing surface conditions or external intervention
DifficultyStandard +0.3 This is a standard M1 connected particles problem with friction. Part (a) is trivial impulse-momentum application (1 mark). Part (b) tests understanding of modeling assumptions. Parts (c-d) require setting up equations of motion with friction and tension, then solving for time and distance - all routine M1 techniques with no novel insight needed. The 7 marks for part (c) suggests multiple steps, but these are standard: resolve forces, apply F=ma, solve equations. Slightly easier than average due to straightforward setup and well-signposted parts.
Spec3.03k Connected particles: pulleys and equilibrium3.03v Motion on rough surface: including inclined planes6.03e Impulse: by a force6.03f Impulse-momentum: relation

Two smooth spheres \(A\) and \(B\), of masses \(2m\) and \(m\) respectively, are connected by a light inextensible string which passes over a smooth fixed pulley as shown. \(A\) is initially at rest on the rough horizontal surface of a table, the coefficient of friction between \(A\) and the table being \(\frac{2}{7}\). \(B\) hangs freely on the end of the vertical portion of the string. \includegraphics{figure_5} \(A\) is now given an impulse, directed away from the pulley, of magnitude \(5m\) Ns.
  1. Show that the system starts to move with speed \(2.5 \text{ ms}^{-1}\). [1 mark]
  2. State which modelling assumption ensures that the tensions in the two sections of the string can be taken to be equal. [1 mark]
Given that \(A\) comes to rest before it reaches the edge of the table and before \(B\) hits the pulley,
  1. find the time taken for the system to come to rest. [7 marks]
  2. Find the distance travelled by \(A\) before it first comes to rest. [4 marks]

AnswerMarks Guidance
(a) \(5m = 2mv\) → \(v = 2.5\)B1
(b) Smooth pulleyB1
(c) \(F = ma\) for each sphere: \(T + \frac{2}{3}(2mg) = 2ma\), \(mg - T = ma\)M1 A1 A1
Add: \(3ma = \frac{11}{7}mg\) → \(a = \frac{11}{21} = 5.13\) ms\(^{-2}\)M1 A1
(d) \(v^2 = u^2 + 2as: 0 = 2.5^2 - 10.27s\) → \(s = 0.609\) mM1 A1 M1 A1 13 marks
**(a)** $5m = 2mv$ → $v = 2.5$ | B1 |

**(b)** Smooth pulley | B1 |

**(c)** $F = ma$ for each sphere: $T + \frac{2}{3}(2mg) = 2ma$, $mg - T = ma$ | M1 A1 A1 |
Add: $3ma = \frac{11}{7}mg$ → $a = \frac{11}{21} = 5.13$ ms$^{-2}$ | M1 A1 |

**(d)** $v^2 = u^2 + 2as: 0 = 2.5^2 - 10.27s$ → $s = 0.609$ m | M1 A1 M1 A1 | 13 marks |
Two smooth spheres $A$ and $B$, of masses $2m$ and $m$ respectively, are connected by a light inextensible string which passes over a smooth fixed pulley as shown. $A$ is initially at rest on the rough horizontal surface of a table, the coefficient of friction between $A$ and the table being $\frac{2}{7}$. $B$ hangs freely on the end of the vertical portion of the string.

\includegraphics{figure_5}

$A$ is now given an impulse, directed away from the pulley, of magnitude $5m$ Ns.

\begin{enumerate}[label=(\alph*)]
\item Show that the system starts to move with speed $2.5 \text{ ms}^{-1}$. [1 mark]
\item State which modelling assumption ensures that the tensions in the two sections of the string can be taken to be equal. [1 mark]
\end{enumerate}

Given that $A$ comes to rest before it reaches the edge of the table and before $B$ hits the pulley,

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{2}
\item find the time taken for the system to come to rest. [7 marks]
\item Find the distance travelled by $A$ before it first comes to rest. [4 marks]
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1  Q5 [13]}}