Edexcel M1 — Question 4 11 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Marks11
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Mark schemeDownload PDF ↗
TopicConstant acceleration (SUVAT)
TypeTime to reach midpoint or specific position
DifficultyModerate -0.8 This is a straightforward M1 kinematics and dynamics question requiring standard SUVAT equations and Newton's second law. Parts (a)-(c) involve routine application of kinematic formulae with given values, while part (d) is a direct F=ma calculation. No problem-solving insight or complex reasoning is needed—just methodical application of well-practiced techniques.
Spec3.02d Constant acceleration: SUVAT formulae3.03c Newton's second law: F=ma one dimension

A car moves in a straight line from \(P\) to \(Q\), a distance of \(420\) m, with constant acceleration. At \(P\) the speed of the car is \(8\) ms\(^{-1}\). At \(Q\) the speed of the car is \(20\) ms\(^{-1}\). Find
  1. the time taken to travel from \(P\) to \(Q\), \hfill [2 marks]
  2. the acceleration of the car, \hfill [2 marks]
  3. the time taken for the car to travel \(240\) m from \(P\). \hfill [4 marks]
Given that the mass of the car is \(1200\) kg and the tractive force of the car is \(900\) N,
  1. find the magnitude of the resistance to the car's motion. \hfill [3 marks]

AnswerMarks Guidance
(a) \(420 = \frac{1}{2}(20 + 8)t\) where \(t = 30\) sM1 A1
(b) \(20 = 8 + 30a\) where \(30a = 12\) and \(a = 0.4\) ms\(^{-2}\)M1 A1
(c) \(s = ut + \frac{1}{2}at^2\); \(240 = 8t + 0.2t^2\)M1 A1
\(t^2 + 40t - 1200 = 0\)M1 A1
\((t - 20)(t + 60) = 0\) where \(t = 20\)M1 A1
(d) \(F = ma\); \(900 - R = 1200(0.4)\) where \(R = 900 - 480 = 420\) NM1 A1 A1 Total: 11 marks
**(a)** $420 = \frac{1}{2}(20 + 8)t$ where $t = 30$ s | M1 A1 |

**(b)** $20 = 8 + 30a$ where $30a = 12$ and $a = 0.4$ ms$^{-2}$ | M1 A1 |

**(c)** $s = ut + \frac{1}{2}at^2$; $240 = 8t + 0.2t^2$ | M1 A1 |

$t^2 + 40t - 1200 = 0$ | M1 A1 |

$(t - 20)(t + 60) = 0$ where $t = 20$ | M1 A1 |

**(d)** $F = ma$; $900 - R = 1200(0.4)$ where $R = 900 - 480 = 420$ N | M1 A1 A1 | **Total: 11 marks**
A car moves in a straight line from $P$ to $Q$, a distance of $420$ m, with constant acceleration. At $P$ the speed of the car is $8$ ms$^{-1}$. At $Q$ the speed of the car is $20$ ms$^{-1}$. Find
\begin{enumerate}[label=(\alph*)]
\item the time taken to travel from $P$ to $Q$, \hfill [2 marks]
\item the acceleration of the car, \hfill [2 marks]
\item the time taken for the car to travel $240$ m from $P$. \hfill [4 marks]
\end{enumerate}
Given that the mass of the car is $1200$ kg and the tractive force of the car is $900$ N,
\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{3}
\item find the magnitude of the resistance to the car's motion. \hfill [3 marks]
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1  Q4 [11]}}