| Exam Board | Edexcel |
|---|---|
| Module | M1 (Mechanics 1) |
| Marks | 9 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | SUVAT in 2D & Gravity |
| Type | Vertical motion: energy loss on impact |
| Difficulty | Moderate -0.8 This is a straightforward kinematics question using standard SUVAT equations with constant acceleration. All three parts require direct application of familiar formulas (s=ut+½at², v²=u²+2as) with no problem-solving insight needed. The rebound condition is clearly stated, and the modelling assumptions are standard textbook responses (no air resistance, particle model). Easier than average due to its routine nature and clear structure. |
| Spec | 3.02h Motion under gravity: vector form |
| Answer | Marks | Guidance |
|---|---|---|
| (a) \(7 = \frac{1}{2}gt^2\) | \(t^2 = 14 + 9.8\) | \(t = 1.20 \text{ s}\) |
| (b) \(v = gt = 11.7 \text{ m s}^{-1}\) | M1 A1; \(0 - 5.8566^2 = -2gh\) | \(h = 1.75 \text{ m}\) |
| Modelled stone as particle, ignored air resistance, etc. | B1 B1 | 9 marks |
(a) $7 = \frac{1}{2}gt^2$ | $t^2 = 14 + 9.8$ | $t = 1.20 \text{ s}$ | M1 A1
(b) $v = gt = 11.7 \text{ m s}^{-1}$ | M1 A1; $0 - 5.8566^2 = -2gh$ | $h = 1.75 \text{ m}$ | A1
Modelled stone as particle, ignored air resistance, etc. | B1 B1 | **9 marks**A stone is dropped from rest at a height of 7 m above horizontal ground. It falls vertically, hits the ground and rebounds vertically upwards with half the speed with which it hit the ground. Calculate
\begin{enumerate}[label=(\alph*)]
\item the time taken for the stone to fall to the ground, [2 marks]
\item the speed with which the stone hits the ground, [2 marks]
\item the height to which the stone rises before it comes to instantaneous rest. [3 marks]
\end{enumerate}
State two modelling assumptions that you have made. [2 marks]
\hfill \mbox{\textit{Edexcel M1 Q3 [9]}}