Edexcel M1 — Question 5 12 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNewton's laws and connected particles
TypeAtwood machine, vertical strings
DifficultyStandard +0.3 This is a standard M1 pulley system question requiring Newton's second law applied to connected particles. Part (a) is routine bookwork with straightforward simultaneous equations. Part (b) adds a mild algebraic twist by relating two scenarios, but the method is still mechanical and predictable for this topic. Slightly easier than average due to its formulaic nature.
Spec3.03k Connected particles: pulleys and equilibrium3.03o Advanced connected particles: and pulleys

Two metal weights \(A\) and \(B\), of masses 2.4 kg and 1.8 kg respectively, are attached to the ends of a light inextensible string which passes over a smooth fixed pulley so that the string hangs vertically on each side. The system is released from rest with the string taut.
  1. Calculate the acceleration of each weight and the tension in the string. [6 marks]
\(A\) is now replaced by a different weight of mass \(m\) kg, where \(m < 1.8\), and the system is again released from rest. The magnitude of the acceleration has half of its previous value.
  1. Calculate the value of \(m\). [6 marks]

AnswerMarks Guidance
(a) \(F = ma\) for each: \(2.4g - T = 2.4a\), \(T - 1.8g = 1.8a\)Add: \(0.6g = 4.2a\) \(a = \frac{1}{7}g = 1.4 \text{ ms}^{-1}\)
(b) Now \(1.8g - T = 1.8(0.7)\) so \(T = 16.38\), and \(T - mg = m(0.7)\)\(10.5m = 16.38\) \(m = 1.56\)
(a) $F = ma$ for each: $2.4g - T = 2.4a$, $T - 1.8g = 1.8a$ | Add: $0.6g = 4.2a$ | $a = \frac{1}{7}g = 1.4 \text{ ms}^{-1}$ | $T = 20.2 \text{ N}$ | M1 A1 A1

(b) Now $1.8g - T = 1.8(0.7)$ so $T = 16.38$, and $T - mg = m(0.7)$ | $10.5m = 16.38$ | $m = 1.56$ | M1 A1 M1 A1 | **12 marks**
Two metal weights $A$ and $B$, of masses 2.4 kg and 1.8 kg respectively, are attached to the ends of a light inextensible string which passes over a smooth fixed pulley so that the string hangs vertically on each side. The system is released from rest with the string taut.
\begin{enumerate}[label=(\alph*)]
\item Calculate the acceleration of each weight and the tension in the string. [6 marks]
\end{enumerate}
$A$ is now replaced by a different weight of mass $m$ kg, where $m < 1.8$, and the system is again released from rest. The magnitude of the acceleration has half of its previous value.
\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item Calculate the value of $m$. [6 marks]
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1  Q5 [12]}}