Edexcel S2 — Question 6 13 marks

Exam BoardEdexcel
ModuleS2 (Statistics 2)
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicApproximating the Binomial to the Poisson distribution
TypeCalculate multiple probabilities using Poisson approximation
DifficultyModerate -0.8 This is a standard S2 textbook question on binomial-Poisson approximation. Parts (a) and (c) test recall of conditions, while parts (b) and (d) involve routine calculations with given parameters (n=120, p=0.008). The comparison in part (d) is straightforward. No problem-solving or novel insight required—purely procedural application of well-rehearsed techniques.
Spec5.02b Expectation and variance: discrete random variables5.02c Linear coding: effects on mean and variance5.02i Poisson distribution: random events model5.02j Poisson formula: P(X=x) = e^(-lambda)*lambda^x/x!5.02k Calculate Poisson probabilities5.02l Poisson conditions: for modelling5.02n Sum of Poisson variables: is Poisson

A shop receives weekly deliveries of 120 eggs from a local farm. The proportion of eggs received from the farm that are broken is 0.008
  1. Explain why it is reasonable to use the binomial distribution to model the number of eggs that are broken in each delivery. [3 marks]
  2. Use the binomial distribution to calculate the probability that at most one egg in a delivery will be broken. [4 marks]
  3. State the conditions under which the binomial distribution can be approximated by the Poisson distribution. [1 mark]
  4. Using the Poisson approximation to the binomial, find the probability that at most one egg in a delivery will be broken. Comment on your answer. [5 marks]

AnswerMarks Guidance
(a)fixed no. of eggs, eggs either broken or not, prob. of each egg being broken is same (assuming no accident breaking group together) B3
(b)let \(X =\) no. of eggs broken in delivery \(\therefore X \sim B(120, 0.008)\) M1
\(P(X \leq 1) = (0.992)^{120} + 120(0.008)(0.992)^{119}\)M1 A1
\(= 0.7505 \text{ (4sf)}\)A1
(c)\(n\) large, \(p\) small B1
(d)\(X \approx \text{Po}(0.96)\) M1
\(P(X \leq 1) = e^{-0.96}(1 + 0.96)\)M1 A1
\(= 0.7505 \text{ (4sf)}\)A1
same value to 4sf, very good approx. for these parametersB1 (13)
(a) | fixed no. of eggs, eggs either broken or not, prob. of each egg being broken is same (assuming no accident breaking group together) | B3 |
(b) | let $X =$ no. of eggs broken in delivery $\therefore X \sim B(120, 0.008)$ | M1 |
| $P(X \leq 1) = (0.992)^{120} + 120(0.008)(0.992)^{119}$ | M1 A1 |
| $= 0.7505 \text{ (4sf)}$ | A1 |
(c) | $n$ large, $p$ small | B1 |
(d) | $X \approx \text{Po}(0.96)$ | M1 |
| $P(X \leq 1) = e^{-0.96}(1 + 0.96)$ | M1 A1 |
| $= 0.7505 \text{ (4sf)}$ | A1 |
| same value to 4sf, very good approx. for these parameters | B1 | (13)
A shop receives weekly deliveries of 120 eggs from a local farm. The proportion of eggs received from the farm that are broken is 0.008

\begin{enumerate}[label=(\alph*)]
\item Explain why it is reasonable to use the binomial distribution to model the number of eggs that are broken in each delivery. [3 marks]
\item Use the binomial distribution to calculate the probability that at most one egg in a delivery will be broken. [4 marks]
\item State the conditions under which the binomial distribution can be approximated by the Poisson distribution. [1 mark]
\item Using the Poisson approximation to the binomial, find the probability that at most one egg in a delivery will be broken. Comment on your answer. [5 marks]
\end{enumerate}

\hfill \mbox{\textit{Edexcel S2  Q6 [13]}}