OCR S1 2013 June — Question 2 7 marks

Exam BoardOCR
ModuleS1 (Statistics 1)
Year2013
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHypothesis test of Spearman’s rank correlation coefficien
TypeDetermine ranks from coefficient
DifficultyModerate -0.8 Part (i) is a straightforward application of Spearman's rank correlation coefficient formula requiring ranking of grades and times, calculating differences, and substituting into the formula - pure procedural recall with no conceptual challenge. Part (ii) requires minimal insight that swapping two ranks with equal d² contributions preserves r_s, but this is a simple pattern recognition task. Both parts are routine S1 exercises with no problem-solving or novel thinking required.
Spec5.08e Spearman rank correlation5.08f Hypothesis test: Spearman rank

  1. The table shows the times, in minutes, spent by five students revising for a test, and the grades that they achieved in the test.
    StudentAnnBillCazDenEd
    Time revising0603510045
    GradeCDEBA
    Calculate Spearman's rank correlation coefficient. [5]
  2. The table below shows the ranks given by two judges to four competitors.
    CompetitorPQRS
    Judge 1 rank1234
    Judge 2 rank3214
    Spearman's rank correlation coefficient for these ranks is denoted by \(r_s\). With the same set of ranks for Judge 1, write down a different set of ranks for Judge 2 which gives the same value of \(r_s\). There is no need to find the value of \(r_s\). [2]

(i)
Answer:
- Ranks: \(5\ 2\ 4\ 1\ 3\) or \(A\ B\ C\ D\ E\) (grades) over \(3\ 4\ 5\ 2\ 1\) or \(3\ 1\ 5\ 2\ 4\)
- \(d^2 4\ 4\ 1\ 1\ 4\)
- \(\Sigma d^2 = 14\) (= 14)
- \(1 - \frac{6\times"14"}{5\times(5^2-1)} = 0.3\) oe
Marks: M1, A1, M1, M1, A1[5]
Guidance:
- Attempt ranks
- Correct ranks; allow both sets reversed. Can be implied by eg \(\Sigma f = 14\)
- Attempt \(\Sigma d^2\) dep 1st M1
- ft \(\Sigma d^2\) dep 1st M1
- If one set reversed, \(r_s = -0.3\) M1A0M1A0
- Use PMCC on ranks: 1st M1A1 as main scheme then: \(\Sigma x = \Sigma y = 15\), \(\Sigma x^2 = \Sigma y^2 = 55\), \(\Sigma xy = 48\)
- \(S_{xx} = S_{yy} = 10\), \(S_{xy} = 3\), allow one arith error M1
- \(r = 3/\sqrt{(10\times10)}\) allow one arith error M1
- \(= 0.3\) A1
(ii)
Answer:
- \(\Sigma d^2 = 8\) or '2 the same and 2 differ by 2' or \(1\ 4\ 3\ 2\)
Marks: M1, A1[2]
Guidance:
- May be implied
- Allow \(d^2 = 8\) or similar
### (i)
**Answer:** 
- Ranks: $5\ 2\ 4\ 1\ 3$ or $A\ B\ C\ D\ E$ (grades) over $3\ 4\ 5\ 2\ 1$ or $3\ 1\ 5\ 2\ 4$
- $d^2 4\ 4\ 1\ 1\ 4$
- $\Sigma d^2 = 14$ (= 14)
- $1 - \frac{6\times"14"}{5\times(5^2-1)} = 0.3$ oe

**Marks:** M1, A1, M1, M1, A1[5]

**Guidance:**
- Attempt ranks
- Correct ranks; allow both sets reversed. Can be implied by eg $\Sigma f = 14$
- Attempt $\Sigma d^2$ dep 1st M1
- ft $\Sigma d^2$ dep 1st M1
- If one set reversed, $r_s = -0.3$ M1A0M1A0
- Use PMCC on ranks: 1st M1A1 as main scheme then: $\Sigma x = \Sigma y = 15$, $\Sigma x^2 = \Sigma y^2 = 55$, $\Sigma xy = 48$
- $S_{xx} = S_{yy} = 10$, $S_{xy} = 3$, allow one arith error M1
- $r = 3/\sqrt{(10\times10)}$ allow one arith error M1
- $= 0.3$ A1

### (ii)
**Answer:** 
- $\Sigma d^2 = 8$ or '2 the same and 2 differ by 2' or $1\ 4\ 3\ 2$

**Marks:** M1, A1[2]

**Guidance:**
- May be implied
- Allow $d^2 = 8$ or similar

---
\begin{enumerate}[label=(\roman*)]
\item The table shows the times, in minutes, spent by five students revising for a test, and the grades that they achieved in the test.

\begin{tabular}{|c|c|c|c|c|c|}
\hline
Student & Ann & Bill & Caz & Den & Ed \\
\hline
Time revising & 0 & 60 & 35 & 100 & 45 \\
\hline
Grade & C & D & E & B & A \\
\hline
\end{tabular}

Calculate Spearman's rank correlation coefficient. [5]

\item The table below shows the ranks given by two judges to four competitors.

\begin{tabular}{|c|c|c|c|c|}
\hline
Competitor & P & Q & R & S \\
\hline
Judge 1 rank & 1 & 2 & 3 & 4 \\
\hline
Judge 2 rank & 3 & 2 & 1 & 4 \\
\hline
\end{tabular}

Spearman's rank correlation coefficient for these ranks is denoted by $r_s$. With the same set of ranks for Judge 1, write down a different set of ranks for Judge 2 which gives the same value of $r_s$. There is no need to find the value of $r_s$. [2]
\end{enumerate}

\hfill \mbox{\textit{OCR S1 2013 Q2 [7]}}