Edexcel S1 — Question 1 4 marks

Exam BoardEdexcel
ModuleS1 (Statistics 1)
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndependent Events
TypeBoth independence and mutual exclusivity
DifficultyModerate -0.8 This is a straightforward probability question testing basic definitions. Part (a) requires only checking if P(A ∩ B) = 0, which is immediate. Part (b) requires finding P(B) using the addition rule (one step), then checking if P(A ∩ B) = P(A)P(B) (one multiplication). Both parts are direct application of definitions with minimal calculation, making this easier than average.
Spec2.03a Mutually exclusive and independent events

Given that \(P(A \cup B) = 0.65\), \(P(A \cap B) = 0.15\) and \(P(A) = 0.3\), determine, with explanation, whether or not the events \(A\) and \(B\) are
  1. mutually exclusive, [1 mark]
  2. independent. [3 marks]

AnswerMarks Guidance
(a) \(P(A \cap B) \neq 0\), so not mutually exclusiveB1
(b) \(0.65 = 0.3 + P(B) - 0.15\) so \(P(B) = 0.5\)M1 A1
\(P(A) \times P(B) = 0.3 \times 0.5 = 0.15 = P(A \cap B)\), so independentA1 Total: 4 marks
(a) $P(A \cap B) \neq 0$, so not mutually exclusive | B1 |

(b) $0.65 = 0.3 + P(B) - 0.15$ so $P(B) = 0.5$ | M1 A1 | 
$P(A) \times P(B) = 0.3 \times 0.5 = 0.15 = P(A \cap B)$, so independent | A1 | **Total: 4 marks**
Given that $P(A \cup B) = 0.65$, $P(A \cap B) = 0.15$ and $P(A) = 0.3$, determine, with explanation, whether or not the events $A$ and $B$ are
\begin{enumerate}[label=(\alph*)]
\item mutually exclusive, [1 mark]
\item independent. [3 marks]
\end{enumerate}

\hfill \mbox{\textit{Edexcel S1  Q1 [4]}}