Edexcel S1 — Question 4 14 marks

Exam BoardEdexcel
ModuleS1 (Statistics 1)
Marks14
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNormal Distribution
TypeMixed calculations with boundaries
DifficultyStandard +0.8 This question requires setting up and solving simultaneous equations using inverse normal distribution (z-scores) from two given percentiles, which goes beyond routine normal distribution problems. Students must recognize that P(X > 200) = 0.01 gives one equation and P(165 < X < 200) = 0.76 combined with the first condition gives another, then solve algebraically for μ and σ². The multi-step algebraic manipulation and conceptual understanding of how percentiles relate to parameters makes this moderately challenging for S1 level.
Spec2.04e Normal distribution: as model N(mu, sigma^2)2.04f Find normal probabilities: Z transformation

The heights of the students at a university are assumed to follow a normal distribution. 1% of the students are over 200 cm tall and 76% are between 165 cm and 200 cm tall. Find
  1. the mean and the variance of the distribution, [9 marks]
  2. the percentage of the students who are under 158 cm tall. [3 marks]
  3. Comment briefly on the suitability of a normal distribution to model such a population. [2 marks]

AnswerMarks Guidance
(a) \(P(X > 200) = 0.01\): \(\frac{200 - \mu}{\sigma} = 2.33\) → \(200 - \mu = 2.33\sigma\)M1 A1 \(P(X > 165) = 0.77\): \(\frac{165 - \mu}{\sigma} = -0.74\) → \(165 - \mu = -0.74\sigma\)
(b) \(P(X < 158) = P(Z < -1.34) = 1 - 0.91\), so 99% are under 158 cmM1 A1 A1
(c) Model may be affected by lack of very short individuals (e.g. children), etc.B2 Total: 14 marks
(a) $P(X > 200) = 0.01$: $\frac{200 - \mu}{\sigma} = 2.33$ → $200 - \mu = 2.33\sigma$ | M1 A1 | $P(X > 165) = 0.77$: $\frac{165 - \mu}{\sigma} = -0.74$ → $165 - \mu = -0.74\sigma$ | B1 M1 A1 | $3.07\sigma = 35$ → $\sigma = 11.4$ | M1 A1 A1 A1 | $\mu = 173$, $\sigma^2 = 130$ |

(b) $P(X < 158) = P(Z < -1.34) = 1 - 0.91$, so 99% are under 158 cm | M1 A1 A1 |

(c) Model may be affected by lack of very short individuals (e.g. children), etc. | B2 | Total: 14 marks

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The heights of the students at a university are assumed to follow a normal distribution. 1% of the students are over 200 cm tall and 76% are between 165 cm and 200 cm tall.
Find
\begin{enumerate}[label=(\alph*)]
\item the mean and the variance of the distribution, [9 marks]
\item the percentage of the students who are under 158 cm tall. [3 marks]
\item Comment briefly on the suitability of a normal distribution to model such a population. [2 marks]
\end{enumerate}

\hfill \mbox{\textit{Edexcel S1  Q4 [14]}}