Edexcel C4 — Question 4 10 marks

Exam BoardEdexcel
ModuleC4 (Core Mathematics 4)
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicParametric curves and Cartesian conversion
TypeFind normal equation
DifficultyModerate -0.3 This is a standard C4 parametric equations question requiring routine techniques: finding axis intersections by substituting x=0 and y=0, recognizing the parametric form as an ellipse for sketching, and finding the normal using dx/dt and dy/dt. All steps are textbook procedures with no novel insight required, making it slightly easier than average.
Spec1.03g Parametric equations: of curves and conversion to cartesian1.07s Parametric and implicit differentiation

A curve is given parametrically by the equations $$x = 5 \cos t, \quad y = -2 + 4 \sin t, \quad 0 \leq t < 2\pi.$$
  1. Find the coordinates of all the points at which \(C\) intersects the coordinate axes, giving your answers in surd form where appropriate. [4]
  2. Sketch the graph at \(C\). [2]
\(P\) is the point on \(C\) where \(t = \frac{1}{6}\pi\).
  1. Show that the normal to \(C\) at \(P\) has equation $$8\sqrt{3}y = 10x - 25\sqrt{3}.$$ [4]

Question 4:
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Question 4:
4
A curve is given parametrically by the equations
$$x = 5 \cos t, \quad y = -2 + 4 \sin t, \quad 0 \leq t < 2\pi.$$

\begin{enumerate}[label=(\alph*)]
\item Find the coordinates of all the points at which $C$ intersects the coordinate axes, giving your answers in surd form where appropriate. [4]
\item Sketch the graph at $C$. [2]
\end{enumerate}

$P$ is the point on $C$ where $t = \frac{1}{6}\pi$.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{2}
\item Show that the normal to $C$ at $P$ has equation
$$8\sqrt{3}y = 10x - 25\sqrt{3}.$$ [4]
\end{enumerate}

\hfill \mbox{\textit{Edexcel C4  Q4 [10]}}