OCR C2 — Question 7 9 marks

Exam BoardOCR
ModuleC2 (Core Mathematics 2)
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndefinite & Definite Integrals
TypePure definite integration
DifficultyModerate -0.8 This is a straightforward integration question testing basic techniques. Part (i) requires standard power rule integration including rewriting 1/√x as x^(-1/2). Part (ii) involves expanding a quadratic and integrating with definite limits. Both parts are routine C2 exercises requiring only direct application of learned rules with no problem-solving or insight needed, making this easier than average.
Spec1.08b Integrate x^n: where n != -1 and sums1.08d Evaluate definite integrals: between limits

  1. Find $$\int \left( x + 5 + \frac{3}{\sqrt{x}} \right) dx.$$ [4]
  2. Evaluate $$\int_{-2}^{0} (3x - 1)^2 dx.$$ [5]

(i)
AnswerMarks
\(= \frac{1}{2}x^2 + 5x + 6x^2 + c\)M1 A3
(ii)
AnswerMarks Guidance
\(= \int_{-2}^{0} (9x^2 - 6x + 1) \, dx\)M1
\(= [3x^3 - 3x^2 + x]_{-2}^{0}\)M1 A1
\(= (0) - (-24 - 12 - 2) = 38\)M1 A1 (9)
## (i)
$= \frac{1}{2}x^2 + 5x + 6x^2 + c$ | M1 A3 |

## (ii)
$= \int_{-2}^{0} (9x^2 - 6x + 1) \, dx$ | M1 |

$= [3x^3 - 3x^2 + x]_{-2}^{0}$ | M1 A1 |

$= (0) - (-24 - 12 - 2) = 38$ | M1 A1 | (9)

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\begin{enumerate}[label=(\roman*)]
\item Find
$$\int \left( x + 5 + \frac{3}{\sqrt{x}} \right) dx.$$ [4]

\item Evaluate
$$\int_{-2}^{0} (3x - 1)^2 dx.$$ [5]
\end{enumerate}

\hfill \mbox{\textit{OCR C2  Q7 [9]}}