Edexcel C2 — Question 7 8 marks

Exam BoardEdexcel
ModuleC2 (Core Mathematics 2)
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRadians, Arc Length and Sector Area
TypeSegment area calculation
DifficultyModerate -0.3 This is a straightforward sector/segment question requiring standard formulas (area = ½r²θ, segment = sector - triangle). Part (a) is simple algebra, (b) applies perimeter formula, and (c) requires subtracting triangle area from sector area. All techniques are routine C2 content with no novel problem-solving required, making it slightly easier than average.
Spec1.05d Radians: arc length s=r*theta and sector area A=1/2 r^2 theta

\includegraphics{figure_2} Fig. 2 shows the sector \(OAB\) of a circle of radius \(r\) cm. The area of the sector is \(15\) cm\(^2\) and \(\angle AOB = 1.5\) radians.
  1. Prove that \(r = 2\sqrt{5}\). [3]
  2. Find, in cm, the perimeter of the sector \(OAB\). [2]
The segment \(R\), shaded in Fig 1, is enclosed by the arc \(AB\) and the straight line \(AB\).
  1. Calculate, to 3 decimal places, the area of \(R\). [3]

AnswerMarks Guidance
(a) \(\frac{1}{2}r^2\theta = \frac{1}{2}r^2 \times 1.5 = 15\)M1 A1
\(r^2 = 20 = \sqrt{(4 \times 5)}\); \(r = 2\sqrt{5}\)A1 (*) (3)
(b) \(r\theta + 2r = 3\sqrt{5} + 4\sqrt{5} = 7\sqrt{5}\) cmM1 A1 (or 15.7, or a.w.r.t 15.65....) (2)
(c) \(\triangle OAB: \frac{1}{2}r^2\sin\theta = 10\sin 1.5 (= 9.9749...)\)M1
Segment area \(= 15 - \triangle OAB = 5.025\) cm²M1 A1 (3)
**(a)** $\frac{1}{2}r^2\theta = \frac{1}{2}r^2 \times 1.5 = 15$ | M1 A1 |

$r^2 = 20 = \sqrt{(4 \times 5)}$; $r = 2\sqrt{5}$ | A1 | (*) (3)

**(b)** $r\theta + 2r = 3\sqrt{5} + 4\sqrt{5} = 7\sqrt{5}$ cm | M1 A1 | (or 15.7, or a.w.r.t 15.65....) (2)

**(c)** $\triangle OAB: \frac{1}{2}r^2\sin\theta = 10\sin 1.5 (= 9.9749...)$ | M1 |

Segment area $= 15 - \triangle OAB = 5.025$ cm² | M1 A1 | (3)
\includegraphics{figure_2}

Fig. 2 shows the sector $OAB$ of a circle of radius $r$ cm. The area of the sector is $15$ cm$^2$ and $\angle AOB = 1.5$ radians.

\begin{enumerate}[label=(\alph*)]
\item Prove that $r = 2\sqrt{5}$. [3]
\item Find, in cm, the perimeter of the sector $OAB$. [2]
\end{enumerate}

The segment $R$, shaded in Fig 1, is enclosed by the arc $AB$ and the straight line $AB$.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{2}
\item Calculate, to 3 decimal places, the area of $R$. [3]
\end{enumerate}

\hfill \mbox{\textit{Edexcel C2  Q7 [8]}}