Edexcel C2 — Question 8 12 marks

Exam BoardEdexcel
ModuleC2 (Core Mathematics 2)
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAreas by integration
TypeArea under polynomial curve
DifficultyModerate -0.3 This is a straightforward C2 question testing basic coordinate geometry, differentiation for tangent equations, and integration with respect to y. All parts are routine applications of standard techniques with no problem-solving insight required. The multi-part structure and 12 marks elevate it slightly above trivial, but it remains easier than average for A-level.
Spec1.07m Tangents and normals: gradient and equations1.08e Area between curve and x-axis: using definite integrals

\includegraphics{figure_1} The curve \(C\), shown in Fig. 1, represents the graph of \(y = \frac{x^2}{25}\), \(x \geq 0\). The points \(A\) and \(B\) on the curve \(C\) have \(x\)-coordinates \(5\) and \(10\) respectively.
  1. Write down the \(y\)-coordinates of \(A\) and \(B\). [1]
  2. Find an equation of the tangent to \(C\) at \(A\). [4]
The finite region \(R\) is enclosed by \(C\), the \(y\)-axis and the lines through \(A\) and \(B\) parallel to the \(x\)-axis.
  1. For points \((x, y)\) on \(C\), express \(x\) in terms of \(y\). [2]
  2. Use integration to find the area of \(R\). [5]

(a)
AnswerMarks
\(A: y = 1\)B1
\(B: y = 4\)
(1 mark)
(b)
AnswerMarks
\(\frac{dy}{dx} = \frac{2x}{25} = \frac{2}{5}\) where \(x = 5\)M1 A1
Tangent: \(y - 1 = \frac{2}{5}(x - 5)\) (or \(5y = 2x - 5\))M1 A1
(4 marks)
(c)
AnswerMarks
\(x = 5y^{\frac{1}{2}}\)B1 B1
(2 marks)
(d)
AnswerMarks
Integrate: \(\frac{5y^{\frac{3}{2}}}{\frac{3}{2}} = \frac{10y^{\frac{3}{2}}}{3}\)M1 A1ft
\(\left[y^4 - 1\right]_1 = \left(\frac{10 \times 4^{\frac{3}{2}}}{3}\right) - \left(\frac{10 \times 1^{\frac{3}{2}}}{3}\right) = \frac{70}{3}\)M1 A1, A1
\((23\frac{1}{3}, 23.3)\)
(5 marks)
(12 marks total)
## (a)
$A: y = 1$ | B1 |
$B: y = 4$ | |
| (1 mark) |

## (b)
$\frac{dy}{dx} = \frac{2x}{25} = \frac{2}{5}$ where $x = 5$ | M1 A1 |
Tangent: $y - 1 = \frac{2}{5}(x - 5)$ (or $5y = 2x - 5$) | M1 A1 |
| (4 marks) |

## (c)
$x = 5y^{\frac{1}{2}}$ | B1 B1 |
| (2 marks) |

## (d)
Integrate: $\frac{5y^{\frac{3}{2}}}{\frac{3}{2}} = \frac{10y^{\frac{3}{2}}}{3}$ | M1 A1ft |
$\left[y^4 - 1\right]_1 = \left(\frac{10 \times 4^{\frac{3}{2}}}{3}\right) - \left(\frac{10 \times 1^{\frac{3}{2}}}{3}\right) = \frac{70}{3}$ | M1 A1, A1 |
$(23\frac{1}{3}, 23.3)$ | |
| (5 marks) |
| **(12 marks total)** |

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\includegraphics{figure_1}

The curve $C$, shown in Fig. 1, represents the graph of $y = \frac{x^2}{25}$, $x \geq 0$.

The points $A$ and $B$ on the curve $C$ have $x$-coordinates $5$ and $10$ respectively.
\begin{enumerate}[label=(\alph*)]
\item Write down the $y$-coordinates of $A$ and $B$. [1]
\item Find an equation of the tangent to $C$ at $A$. [4]
\end{enumerate}
The finite region $R$ is enclosed by $C$, the $y$-axis and the lines through $A$ and $B$ parallel to the $x$-axis.
\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{2}
\item For points $(x, y)$ on $C$, express $x$ in terms of $y$. [2]
\item Use integration to find the area of $R$. [5]
\end{enumerate}

\hfill \mbox{\textit{Edexcel C2  Q8 [12]}}