Edexcel C2 — Question 6 9 marks

Exam BoardEdexcel
ModuleC2 (Core Mathematics 2)
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLaws of Logarithms
TypeTwo unrelated log parts: one non-log algebraic part
DifficultyModerate -0.3 This is a multi-part C2 question combining recurrence relations and logarithms. Part (a) requires setting up and solving a quadratic equation from the recurrence relation (routine algebra), part (b) is trivial recall of log laws, and part (c) applies standard logarithm rules. The question is slightly easier than average as it's mostly procedural with clear signposting and no conceptual challenges beyond applying learned techniques.
Spec1.04e Sequences: nth term and recurrence relations1.06f Laws of logarithms: addition, subtraction, power rules

The sequence \(u_1, u_2, u_3, \ldots, u_n\) is defined by the recurrence relation $$u_{n+1} = pu_n + 5, u_1 = 2, \text{ where } p \text{ is a constant.}$$ Given that \(u_3 = 8\),
  1. show that one possible value of \(p\) is \(\frac{1}{2}\) and find the other value of \(p\). [5]
Using \(p = \frac{1}{2}\),
  1. write down the value of \(\log_2 p\). [1]
Given also that \(\log_2 q = t\),
  1. express \(\log_2 \left(\frac{p^3}{\sqrt{q}}\right)\) in terms of \(t\). [3]

Part (a)
AnswerMarks Guidance
\(u_2 = 2p + 5\)B1
\(u_3 = p(2p + 5) + 5\)M1
\(8 = 2p^2 + 5p + 5\) or \(2p^2 + 5p - 3 = 0\)M1
\((2p - 1)(p + 3) = 0\)M1
\(p = -3\) or \(\frac{1}{2}\)A1, B1 cso (5 marks)
Part (b)
AnswerMarks Guidance
\(\log_2 \left(\frac{1}{2}\right) = \log_2 2^{-1} = -1\)B1 (1 mark)
Part (c)
AnswerMarks Guidance
\(\log_2 \left(\frac{p^3}{\sqrt{q}}\right) = \log_2 p^3 - \log_2 \sqrt{q}\)Use of \(\log a - \log b\) M1
\(b\)
\(= 3\log_2 p - \frac{1}{2}\log_2 q\)Use of \(\log a^n\) M1
\(= -3 - \frac{1}{2}t\)accept \(3\log_2 p - \frac{1}{2}t\) A1 ft
Total for Question 6: 9 marks
**Part (a)**
$u_2 = 2p + 5$ | B1 |
$u_3 = p(2p + 5) + 5$ | M1 |
$8 = 2p^2 + 5p + 5$ or $2p^2 + 5p - 3 = 0$ | M1 |
$(2p - 1)(p + 3) = 0$ | M1 |
$p = -3$ or $\frac{1}{2}$ | A1, B1 cso | (5 marks)

**Part (b)**
$\log_2 \left(\frac{1}{2}\right) = \log_2 2^{-1} = -1$ | B1 | (1 mark)

**Part (c)**
$\log_2 \left(\frac{p^3}{\sqrt{q}}\right) = \log_2 p^3 - \log_2 \sqrt{q}$ | Use of $\log a - \log b$ | M1 |
$b$ | | |
$= 3\log_2 p - \frac{1}{2}\log_2 q$ | Use of $\log a^n$ | M1 |
$= -3 - \frac{1}{2}t$ | accept $3\log_2 p - \frac{1}{2}t$ | A1 ft | (3 marks)

**Total for Question 6: 9 marks**

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The sequence $u_1, u_2, u_3, \ldots, u_n$ is defined by the recurrence relation
$$u_{n+1} = pu_n + 5, u_1 = 2, \text{ where } p \text{ is a constant.}$$
Given that $u_3 = 8$,
\begin{enumerate}[label=(\alph*)]
\item show that one possible value of $p$ is $\frac{1}{2}$ and find the other value of $p$. [5]
\end{enumerate}
Using $p = \frac{1}{2}$,
\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item write down the value of $\log_2 p$. [1]
\end{enumerate}
Given also that $\log_2 q = t$,
\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{2}
\item express $\log_2 \left(\frac{p^3}{\sqrt{q}}\right)$ in terms of $t$. [3]
\end{enumerate}

\hfill \mbox{\textit{Edexcel C2  Q6 [9]}}