OCR C1 — Question 6 10 marks

Exam BoardOCR
ModuleC1 (Core Mathematics 1)
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircles
TypeCircle through three points using right angle in semicircle
DifficultyModerate -0.3 This is a straightforward multi-part question testing standard C1 circle techniques: showing perpendicularity using gradients, finding the centre as the midpoint of a diameter (using the right-angle-in-semicircle property), and converting to general form. All parts follow routine procedures with no problem-solving insight required, making it slightly easier than average.
Spec1.03b Straight lines: parallel and perpendicular relationships1.03d Circles: equation (x-a)^2+(y-b)^2=r^21.03e Complete the square: find centre and radius of circle

The points \(P\), \(Q\) and \(R\) have coordinates \((-5, 2)\), \((-3, 8)\) and \((9, 4)\) respectively.
  1. Show that \(\angle PQR = 90°\). [4]
Given that \(P\), \(Q\) and \(R\) all lie on a circle,
  1. find the coordinates of the centre of the circle, [3]
  2. show that the equation of the circle can be written in the form $$x^2 + y^2 - 4x - 6y = k,$$ where \(k\) is an integer to be found. [3]

The points $P$, $Q$ and $R$ have coordinates $(-5, 2)$, $(-3, 8)$ and $(9, 4)$ respectively.
\begin{enumerate}[label=(\roman*)]
\item Show that $\angle PQR = 90°$. [4]
\end{enumerate}

Given that $P$, $Q$ and $R$ all lie on a circle,
\begin{enumerate}[label=(\roman*)]
\setcounter{enumi}{1}
\item find the coordinates of the centre of the circle, [3]
\item show that the equation of the circle can be written in the form
$$x^2 + y^2 - 4x - 6y = k,$$
where $k$ is an integer to be found. [3]
\end{enumerate}

\hfill \mbox{\textit{OCR C1  Q6 [10]}}