| Exam Board | OCR |
|---|---|
| Module | C1 (Core Mathematics 1) |
| Marks | 4 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Indices and Surds |
| Type | Solve exponential equations |
| Difficulty | Moderate -0.5 This is a standard indices equation requiring conversion to the same base (powers of 2) and equating exponents. It's slightly easier than average as it's a straightforward procedural question with clear steps: rewrite as 2^(2y+2) = 2^(6y-3), equate exponents, solve linear equation. No conceptual difficulty beyond basic index laws. |
| Spec | 1.02a Indices: laws of indices for rational exponents1.06g Equations with exponentials: solve a^x = b |
Find the value of $y$ such that
$$4^{y+1} = 8^{2y-1}.$$ [4]
\hfill \mbox{\textit{OCR C1 Q1 [4]}}