Edexcel C1 — Question 6 7 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicArithmetic Sequences and Series
TypeSigma notation: arithmetic series evaluation
DifficultyModerate -0.8 This is a straightforward C1 arithmetic series question requiring standard formula application. Part (a) involves recognizing an arithmetic sequence and applying the sum formula with clear first/last terms. Part (b) requires algebraic manipulation to separate the sum into standard results (Σr and Σ1), then factorizing to match the given form—routine techniques with no conceptual challenges or novel problem-solving required.
Spec1.04g Sigma notation: for sums of series1.04h Arithmetic sequences: nth term and sum formulae

  1. Evaluate $$\sum_{r=1}^{50} (80 - 3r).$$ [3]
  2. Show that $$\sum_{r=1}^{n} \frac{r + 3}{2} = k n(n + 7),$$ where \(k\) is a rational constant to be found. [4]

AnswerMarks Guidance
(a) AP: \(a = 77, l = -70\)B1
\(S_{50} = \frac{50}{2}[77 + (-70)] = 25 \times 7 = 175\)M1 A1
(b) AP: \(a = 2, d = \frac{1}{4}\)B2
\(S_n = \frac{n}{2}[4 + \frac{1}{4}(n-1)]\)M1
\(= \frac{1}{4}n[8 + (n-1)] = \frac{1}{4}n(n + 7)\)A1 \([k = \frac{1}{4}]\)
**(a)** AP: $a = 77, l = -70$ | B1 |
$S_{50} = \frac{50}{2}[77 + (-70)] = 25 \times 7 = 175$ | M1 A1 |

**(b)** AP: $a = 2, d = \frac{1}{4}$ | B2 |
$S_n = \frac{n}{2}[4 + \frac{1}{4}(n-1)]$ | M1 |
$= \frac{1}{4}n[8 + (n-1)] = \frac{1}{4}n(n + 7)$ | A1 | $[k = \frac{1}{4}]$ | (7)
\begin{enumerate}[label=(\alph*)]
\item Evaluate
$$\sum_{r=1}^{50} (80 - 3r).$$ [3]

\item Show that
$$\sum_{r=1}^{n} \frac{r + 3}{2} = k n(n + 7),$$
where $k$ is a rational constant to be found. [4]
\end{enumerate}

\hfill \mbox{\textit{Edexcel C1  Q6 [7]}}