Edexcel C1 — Question 6 8 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCompleting the square and sketching
TypeComplete square then solve equation
DifficultyModerate -0.8 This is a straightforward C1 completing the square question with standard parts: complete the square (routine algebraic manipulation), state line of symmetry (direct read-off), and solve a quadratic equation using the completed square form. All parts follow textbook procedures with no problem-solving or novel insight required, making it easier than average but not trivial due to the multi-step nature.
Spec1.02d Quadratic functions: graphs and discriminant conditions1.02e Complete the square: quadratic polynomials and turning points1.02f Solve quadratic equations: including in a function of unknown

$$\text{f}(x) = 2x^2 - 4x + 1.$$
  1. Find the values of the constants \(a\), \(b\) and \(c\) such that $$\text{f}(x) = a(x + b)^2 + c.$$ [4]
  2. State the equation of the line of symmetry of the curve \(y = \text{f}(x)\). [1]
  3. Solve the equation \(\text{f}(x) = 3\), giving your answers in exact form. [3]

AnswerMarks Guidance
(a)\(f(x) = 2[x^2 - 2x] + 1\) M1
\(= 2[(x-1)^2 - 1] + 1\)M1
\(= 2(x-1)^2 - 1,\) \(a = 2, b = -1, c = -1\)A2
(b)\(x = 1\) B1
(c)\(2(x-1)^2 - 1 = 3\) M1
\((x-1)^2 = 2\)M1 A1
\(x = 1 \pm \sqrt{2}\)M1 A1 (8)
(a) | $f(x) = 2[x^2 - 2x] + 1$ | M1 |
| $= 2[(x-1)^2 - 1] + 1$ | M1 |
| $= 2(x-1)^2 - 1,$ $a = 2, b = -1, c = -1$ | A2 |

(b) | $x = 1$ | B1 |

(c) | $2(x-1)^2 - 1 = 3$ | M1 |
| $(x-1)^2 = 2$ | M1 A1 |
| $x = 1 \pm \sqrt{2}$ | M1 A1 | (8)
$$\text{f}(x) = 2x^2 - 4x + 1.$$

\begin{enumerate}[label=(\alph*)]
\item Find the values of the constants $a$, $b$ and $c$ such that
$$\text{f}(x) = a(x + b)^2 + c.$$ [4]

\item State the equation of the line of symmetry of the curve $y = \text{f}(x)$. [1]

\item Solve the equation $\text{f}(x) = 3$, giving your answers in exact form. [3]
\end{enumerate}

\hfill \mbox{\textit{Edexcel C1  Q6 [8]}}