Edexcel C1 — Question 10 11 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStraight Lines & Coordinate Geometry
TypeRectangle or parallelogram vertices
DifficultyModerate -0.5 This is a straightforward C1 coordinate geometry question requiring standard techniques: finding gradients using perpendicularity, applying Pythagoras' theorem, and solving a simple quadratic. While multi-part with 11 marks total, each step follows directly from the previous with no novel insight required, making it slightly easier than average.
Spec1.03a Straight lines: equation forms y=mx+c, ax+by+c=01.03b Straight lines: parallel and perpendicular relationships

\includegraphics{figure_1} The points \(A(3, 0)\) and \(B(0, 4)\) are two vertices of the rectangle \(ABCD\), as shown in Fig. 1.
  1. Write down the gradient of \(AB\) and hence the gradient of \(BC\). [3]
The point \(C\) has coordinates \((8, k)\), where \(k\) is a positive constant.
  1. Find the length of \(BC\) in terms of \(k\). [2]
Given that the length of \(BC\) is 10 and using your answer to part (b),
  1. find the value of \(k\), [4]
  2. find the coordinates of \(D\). [2]

Part (a)
AnswerMarks
\(AB\): \(M = -\frac{4}{3}\); \(BC\): \(M = \frac{3}{4}\)B1, M1, A1 ft (3)
Part (b)
AnswerMarks
\(BC = \sqrt{8^2 + (k-4)^2}\) (= \(\sqrt{k^2 - 8k + 80}\))M1 A1 (2)
Part (c)
AnswerMarks
\((k^2 - 8k + 80) = 100\) (their \(BC^2 = 100\))M1
\(k^2 - 8k - 20 = 0\) → \((k-10)(k+2) = 0\)
AnswerMarks
\(k = 10\), \(k = -2\) (rejected)M1 A1 (4)
Part (d)
AnswerMarks
\((11, 6)\)B1 B1 (2)
Total: 11 marks
## Part (a)
$AB$: $M = -\frac{4}{3}$; $BC$: $M = \frac{3}{4}$ | B1, M1, A1 ft (3)

## Part (b)
$BC = \sqrt{8^2 + (k-4)^2}$ (= $\sqrt{k^2 - 8k + 80}$) | M1 A1 (2)

## Part (c)
$(k^2 - 8k + 80) = 100$ (their $BC^2 = 100$) | M1

$k^2 - 8k - 20 = 0$ → $(k-10)(k+2) = 0$

$k = 10$, $k = -2$ (rejected) | M1 A1 (4)

## Part (d)
$(11, 6)$ | B1 B1 (2)

**Total: 11 marks**
\includegraphics{figure_1}

The points $A(3, 0)$ and $B(0, 4)$ are two vertices of the rectangle $ABCD$, as shown in Fig. 1.

\begin{enumerate}[label=(\alph*)]
\item Write down the gradient of $AB$ and hence the gradient of $BC$. [3]
\end{enumerate}

The point $C$ has coordinates $(8, k)$, where $k$ is a positive constant.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item Find the length of $BC$ in terms of $k$. [2]
\end{enumerate}

Given that the length of $BC$ is 10 and using your answer to part (b),

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{2}
\item find the value of $k$, [4]
\item find the coordinates of $D$. [2]
\end{enumerate}

\hfill \mbox{\textit{Edexcel C1  Q10 [11]}}