Edexcel S3 Specimen — Question 4 11 marks

Exam BoardEdexcel
ModuleS3 (Statistics 3)
SessionSpecimen
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHypothesis test of Spearman’s rank correlation coefficien
TypeHandle tied ranks
DifficultyStandard +0.3 This is a straightforward application of Spearman's rank correlation coefficient with standard hypothesis testing. Part (a) requires ranking data and applying the formula (routine calculation), part (b) is standard hypothesis test procedure with critical value lookup, and part (c) asks for recall of how to handle ties. No novel problem-solving or complex reasoning required—slightly easier than average due to small dataset and direct application of learned procedures.
Spec5.08e Spearman rank correlation5.08f Hypothesis test: Spearman rank

At the end of a season a league of eight ice hockey clubs produced the following table showing the position of each club in the league and the average attendances (in hundreds) at home matches.
Club\(A\)\(B\)\(C\)\(D\)\(E\)\(F\)\(G\)\(H\)
Position12345678
Average3738192734262232
  1. Calculate the Spearman rank correlation coefficient between position in the league and average home attendance. [5]
  2. Stating clearly your hypotheses and using a 5\% two-tailed test, interpret your rank correlation coefficient. [4]
Many sets of data include tied ranks.
  1. Explain briefly how tied ranks can be dealt with. [2]

(a)
AnswerMarks Guidance
Attendance ranks 2, 1, 8, 5, 3, 6, 7, 4B1
\(\sum d^2 = 48\)M1 A1 Attempt to find \(\sum d^2\)
\(r_s = 1 - \frac{6 \times 48}{8 \times 63}\)M1 Substitution of their \(\sum d^2\)
\(= 0.4286\)A1 ft awrt 0.429
(5 marks)
(b)
AnswerMarks Guidance
\(H_0 : \rho = 0; H_1 : \rho \neq 0\)B1 both
With \(n=8\), critical value is 0.7381B1
Since 0.429 is not in the critical region (\(\rho < -0.7381\) or \(\rho > 0.7381\)) then there is no evidence to reject \(H_0\), and it can be concluded that at the 5% level there is no evidence of correlation between league position and attendanceM1 Correct comparison
A1 ftConclusion
(4 marks)
(c)
AnswerMarks
Share ranks evenly.B1
Use product moment correlation coefficient on ranks.B1
(2 marks)
## (a)
Attendance ranks 2, 1, 8, 5, 3, 6, 7, 4 | B1 |
$\sum d^2 = 48$ | M1 A1 | Attempt to find $\sum d^2$
$r_s = 1 - \frac{6 \times 48}{8 \times 63}$ | M1 | Substitution of their $\sum d^2$
$= 0.4286$ | A1 ft | awrt 0.429
| (5 marks) |

## (b)
$H_0 : \rho = 0; H_1 : \rho \neq 0$ | B1 | both
With $n=8$, critical value is 0.7381 | B1 |
Since 0.429 is not in the critical region ($\rho < -0.7381$ or $\rho > 0.7381$) then there is no evidence to reject $H_0$, and it can be concluded that at the 5% level there is no evidence of correlation between league position and attendance | M1 | Correct comparison
| A1 ft | Conclusion
| (4 marks) |

## (c)
Share ranks evenly. | B1 |
Use product moment correlation coefficient on ranks. | B1 |
| (2 marks) |
At the end of a season a league of eight ice hockey clubs produced the following table showing the position of each club in the league and the average attendances (in hundreds) at home matches.

\begin{center}
\begin{tabular}{|l|c|c|c|c|c|c|c|c|}
\hline
Club & $A$ & $B$ & $C$ & $D$ & $E$ & $F$ & $G$ & $H$ \\
\hline
Position & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\
\hline
Average & 37 & 38 & 19 & 27 & 34 & 26 & 22 & 32 \\
\hline
\end{tabular}
\end{center}

\begin{enumerate}[label=(\alph*)]
\item Calculate the Spearman rank correlation coefficient between position in the league and average home attendance. [5]

\item Stating clearly your hypotheses and using a 5\% two-tailed test, interpret your rank correlation coefficient. [4]
\end{enumerate}

Many sets of data include tied ranks.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{2}
\item Explain briefly how tied ranks can be dealt with. [2]
\end{enumerate}

\hfill \mbox{\textit{Edexcel S3  Q4 [11]}}