Edexcel S3 — Question 5 12 marks

Exam BoardEdexcel
ModuleS3 (Statistics 3)
Marks12
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Mark schemeDownload PDF ↗
TopicLinear combinations of normal random variables
TypeTwo or more different variables
DifficultyModerate -0.3 This is a straightforward application of standard results for linear combinations of independent normal random variables. Parts (a)-(c) require direct use of E(aX+bY) and Var(aX+bY) formulas plus a normal probability calculation. Part (d) extends this to multiple variables but uses the same principles. All steps are routine with no problem-solving insight required, making it slightly easier than average for A-level.
Spec5.04a Linear combinations: E(aX+bY), Var(aX+bY)5.04b Linear combinations: of normal distributions

The random variable \(R\) is defined as \(R = X + 4Y\) where \(X \sim \text{N}(8, 2^2)\), \(Y \sim \text{N}(14, 3^2)\) and \(X\) and \(Y\) are independent. Find
  1. E\((R)\), [2]
  2. Var\((R)\), [3]
  3. P\((R < 41)\) [3]
The random variables \(Y_1\), \(Y_2\) and \(Y_3\) are independent and each has the same distribution as \(Y\). The random variable \(S\) is defined as $$S = \sum_{i=1}^{3} Y_i - \frac{1}{2}X.$$
  1. Find Var\((S)\). [4]

Part (a)
AnswerMarks
\(E(R) = E(X) + 4E(Y) = 8 + (4 \times 14) = 64\)M1 A1
Total: 2 marks
Part (b)
AnswerMarks
\(\text{Var}(R) = \text{Var}(X) + 16\text{Var}(Y) = 2^2 + (16 \times 3^2)\)M1 A1
\(= 148\)A1
Total: 3 marks
Part (c)
AnswerMarks
\(P(R < 41) = P\left(Z < \frac{41 - 64}{\sqrt{148}}\right) = P(Z < -1.89)\)M1 A1 \(\checkmark\)
\(= 0.0294\)A1
Total: 3 marks
Part (d)
AnswerMarks
\(\text{Var}(S) = 3\text{Var}(Y) + \left(\frac{1}{2}\right)^2 \text{Var}(X)\)M1 M1
\(= 27 + 1\)A1
\(= 28\)A1
Total: 4 marks
## Part (a)
| $E(R) = E(X) + 4E(Y) = 8 + (4 \times 14) = 64$ | M1 A1 |
| **Total: 2 marks** |

## Part (b)
| $\text{Var}(R) = \text{Var}(X) + 16\text{Var}(Y) = 2^2 + (16 \times 3^2)$ | M1 A1 |
| $= 148$ | A1 |
| **Total: 3 marks** |

## Part (c)
| $P(R < 41) = P\left(Z < \frac{41 - 64}{\sqrt{148}}\right) = P(Z < -1.89)$ | M1 A1 $\checkmark$ |
| $= 0.0294$ | A1 |
| **Total: 3 marks** |

## Part (d)
| $\text{Var}(S) = 3\text{Var}(Y) + \left(\frac{1}{2}\right)^2 \text{Var}(X)$ | M1 M1 |
| $= 27 + 1$ | A1 |
| $= 28$ | A1 |
| **Total: 4 marks** |

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The random variable $R$ is defined as $R = X + 4Y$ where $X \sim \text{N}(8, 2^2)$, $Y \sim \text{N}(14, 3^2)$ and $X$ and $Y$ are independent.

Find
\begin{enumerate}[label=(\alph*)]
\item E$(R)$, [2]

\item Var$(R)$, [3]

\item P$(R < 41)$ [3]
\end{enumerate}

The random variables $Y_1$, $Y_2$ and $Y_3$ are independent and each has the same distribution as $Y$. The random variable $S$ is defined as
$$S = \sum_{i=1}^{3} Y_i - \frac{1}{2}X.$$

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{3}
\item Find Var$(S)$. [4]
\end{enumerate}

\hfill \mbox{\textit{Edexcel S3  Q5 [12]}}