Edexcel S3 2009 June — Question 8 11 marks

Exam BoardEdexcel
ModuleS3 (Statistics 3)
Year2009
SessionJune
Marks11
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TopicLinear combinations of normal random variables
TypeComparison involving sums or multiples
DifficultyStandard +0.3 This is a straightforward application of standard results for linear combinations of normal random variables. Parts (a) and (b) require direct use of E(aX + bY) and Var(aX + bY) formulas with no problem-solving. Part (c) involves finding P(B > A) = P(B - A > 0), requiring recognition that B - A is normal, then calculating its mean and variance before using tables—mechanical but slightly more involved than average. Overall slightly easier than a typical A-level question due to being purely procedural.
Spec5.04a Linear combinations: E(aX+bY), Var(aX+bY)5.04b Linear combinations: of normal distributions

The random variable \(A\) is defined as $$A = 4X - 3Y$$ where \(X \sim \text{N}(30, 3^2)\), \(Y \sim \text{N}(20, 2^2)\) and \(X\) and \(Y\) are independent. Find
  1. E(\(A\)), [2]
  2. Var(\(A\)). [3]
The random variables \(Y_1\), \(Y_2\), \(Y_3\) and \(Y_4\) are independent and each has the same distribution as \(Y\). The random variable \(B\) is defined as $$B = \sum_{i=1}^{4} Y_i$$
  1. Find P(\(B > A\)). [6]

The random variable $A$ is defined as
$$A = 4X - 3Y$$
where $X \sim \text{N}(30, 3^2)$, $Y \sim \text{N}(20, 2^2)$ and $X$ and $Y$ are independent.

Find
\begin{enumerate}[label=(\alph*)]
\item E($A$), [2]

\item Var($A$). [3]
\end{enumerate}

The random variables $Y_1$, $Y_2$, $Y_3$ and $Y_4$ are independent and each has the same distribution as $Y$. The random variable $B$ is defined as
$$B = \sum_{i=1}^{4} Y_i$$

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{2}
\item Find P($B > A$). [6]
\end{enumerate}

\hfill \mbox{\textit{Edexcel S3 2009 Q8 [11]}}