Edexcel S2 2009 January — Question 3 7 marks

Exam BoardEdexcel
ModuleS2 (Statistics 2)
Year2009
SessionJanuary
Marks7
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Mark schemeDownload PDF ↗
TopicHypothesis test of binomial distributions
TypeTwo-tailed test critical region
DifficultyModerate -0.3 This is a standard S2 hypothesis testing question requiring routine application of binomial tables to find critical regions and interpret results. While it involves multiple steps (finding two-tailed critical values, calculating actual significance level, and drawing a conclusion), each step follows a well-practiced procedure with no novel problem-solving required. It's slightly easier than average because the mechanics are straightforward once you know the method, though the two-tailed aspect and actual significance level calculation add minor complexity.
Spec2.05b Hypothesis test for binomial proportion2.05c Significance levels: one-tail and two-tail

A single observation \(x\) is to be taken from a Binomial distribution B(20, \(p\)). This observation is used to test \(H_0 : p = 0.3\) against \(H_1 : p \neq 0.3\)
  1. Using a 5\% level of significance, find the critical region for this test. The probability of rejecting either tail should be as close as possible to 2.5\%. [3]
  2. State the actual significance level of this test. [2]
The actual value of \(x\) obtained is 3.
  1. State a conclusion that can be drawn based on this value giving a reason for your answer. [2]

Part (a)
AnswerMarks Guidance
\(X \sim B(20, 0.3)\)M1
\(P(X \leq 2) = 0.0355\)
\(P(X \geq 11) = 1 - 0.9829 = 0.0171\)
Critical region is \((X \leq 2) \cup (X \geq 11)\)A1, A1 (3 marks)
Part (b)
AnswerMarks Guidance
Significance level \(= 0.0355 + 0.0171 = 0.0526\) or 5.26%M1, A1 (2 marks)
Part (c)
AnswerMarks
Insufficient evidence to reject \(H_0\) Or sufficient evidence to accept \(H_0\)/not significant; \(x = 3\) (or the value) is not in the critical region or \(0.1071 > 0.025\)B1 ft, B1 ft
Do not allow inconsistent comments(2 marks)
## Part (a)
$X \sim B(20, 0.3)$ | M1 |
$P(X \leq 2) = 0.0355$ | 
$P(X \geq 11) = 1 - 0.9829 = 0.0171$ |
Critical region is $(X \leq 2) \cup (X \geq 11)$ | A1, A1 | (3 marks)

## Part (b)
Significance level $= 0.0355 + 0.0171 = 0.0526$ or 5.26% | M1, A1 | (2 marks)

## Part (c)
Insufficient evidence to reject $H_0$ Or sufficient evidence to accept $H_0$/not significant; $x = 3$ (or the value) is not in the critical region or $0.1071 > 0.025$ | B1 ft, B1 ft |
Do not allow inconsistent comments | (2 marks)

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A single observation $x$ is to be taken from a Binomial distribution B(20, $p$).

This observation is used to test $H_0 : p = 0.3$ against $H_1 : p \neq 0.3$

\begin{enumerate}[label=(\alph*)]
\item Using a 5\% level of significance, find the critical region for this test. The probability of rejecting either tail should be as close as possible to 2.5\%. [3]
\item State the actual significance level of this test. [2]
\end{enumerate}

The actual value of $x$ obtained is 3.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{2}
\item State a conclusion that can be drawn based on this value giving a reason for your answer. [2]
\end{enumerate}

\hfill \mbox{\textit{Edexcel S2 2009 Q3 [7]}}