Edexcel M3 2003 June — Question 3 9 marks

Exam BoardEdexcel
ModuleM3 (Mechanics 3)
Year2003
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVariable Force
TypeVariable force (position x) - find velocity
DifficultyStandard +0.3 This is a standard M3 variable force problem requiring F=ma with v dv/dx, integration of a polynomial, and applying boundary conditions. The setup is straightforward with clear given information, and the mathematical steps (integrating x(4-3x) and substituting x=6) are routine for M3 students, making it slightly easier than average.
Spec3.02f Non-uniform acceleration: using differentiation and integration3.03d Newton's second law: 2D vectors6.06a Variable force: dv/dt or v*dv/dx methods

A toy car of mass \(0.2\) kg is travelling in a straight line on a horizontal floor. The car is modelled as a particle. At time \(t = 0\) the car passes through a fixed point \(O\). After \(t\) seconds the speed of the car is \(v \text{ m s}^{-1}\) and the car is at a point \(P\) with \(OP = x\) metres. The resultant force on the car is modelled as \(\frac{1}{5}x(4 - 3x)\) N in the direction \(OP\). The car comes to instantaneous rest when \(x = 6\). Find
  1. an expression for \(v^2\) in terms of \(x\), [7]
  2. the initial speed of the car. [2]

A toy car of mass $0.2$ kg is travelling in a straight line on a horizontal floor. The car is modelled as a particle. At time $t = 0$ the car passes through a fixed point $O$. After $t$ seconds the speed of the car is $v \text{ m s}^{-1}$ and the car is at a point $P$ with $OP = x$ metres. The resultant force on the car is modelled as $\frac{1}{5}x(4 - 3x)$ N in the direction $OP$. The car comes to instantaneous rest when $x = 6$.

Find
\begin{enumerate}[label=(\alph*)]
\item an expression for $v^2$ in terms of $x$, [7]
\item the initial speed of the car. [2]
\end{enumerate}

\hfill \mbox{\textit{Edexcel M3 2003 Q3 [9]}}