Edexcel M3 2005 January — Question 4 10 marks

Exam BoardEdexcel
ModuleM3 (Mechanics 3)
Year2005
SessionJanuary
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSimple Harmonic Motion
TypeTime to travel between positions
DifficultyStandard +0.8 This is a multi-part SHM question requiring understanding of the position-time relationship, use of inverse trigonometric functions, and careful geometric reasoning about the window positions. Part (a) requires setting up equations for positions at different times and algebraic manipulation to reach the given result. Parts (b) and (c) involve velocity calculations and time intervals in SHM. While the techniques are standard M3 content, the question requires careful setup, multiple steps, and the 'show that' proof in part (a) adds difficulty since students must arrive at a specific form.
Spec4.10f Simple harmonic motion: x'' = -omega^2 x

In a game at a fair, a small target \(C\) moves horizontally with simple harmonic motion between the points \(A\) and \(B\), where \(AB = 4L\). The target moves inside a box and takes 3 s to travel from \(A\) to \(B\). A player has to shoot at \(C\), but \(C\) is only visible to the player when it passes a window \(PQ\), where \(PQ = b\). The window is initially placed with \(Q\) at the point as shown in Figure 4. The target \(C\) takes 0.75 s to pass from \(Q\) to \(P\).
  1. Show that \(b = (2 - \sqrt{2})L\). [5]
  2. Find the speed of \(C\) as it passes \(P\). [2]
\includegraphics{figure_5} For advanced players, the window \(PQ\) is moved to the centre of \(AB\) so that \(AP = QB\), as shown in Figure 5.
  1. Find the time, in seconds to 2 decimal places, taken for \(C\) to pass from \(Q\) to \(P\) in this new position. [3]

Part (a)
AnswerMarks Guidance
ContentMarks Notes
\(G = 2\pi\mu_4 \Rightarrow \omega = \frac{\pi}{3}\)M1
\(a = 2L\)B1
\(x = 2L\cos \omega t\)M1
\(2L - b = 2L\cos\left(\frac{\pi}{3} - \frac{\pi}{6}\right)\)A1 M1
\(b = L(2-\sqrt{2})\)A1 esc. (5)
Part (b)
AnswerMarks Guidance
ContentMarks Notes
\(\dot{x} = -2L\omega\sin\omega t = -2L\frac{\pi}{3}\sin\frac{\pi}{6}\)M1
Speed \(= \frac{2L\pi}{3}\)A1 (2)
Part (c)
AnswerMarks Guidance
ContentMarks Notes
\(\frac{1}{2}(2-\sqrt{2})L = 2L\sin\omega t\)M1
\(t = 0.1467\)A1
Total time \(= 2 \times 0.1467 = 0.293\) (2 d.p.)A1 (3), (10)
## Part (a)

| Content | Marks | Notes |
|---------|-------|-------|
| $G = 2\pi\mu_4 \Rightarrow \omega = \frac{\pi}{3}$ | M1 | |
| $a = 2L$ | B1 | |
| $x = 2L\cos \omega t$ | M1 | |
| $2L - b = 2L\cos\left(\frac{\pi}{3} - \frac{\pi}{6}\right)$ | A1 M1 | |
| $b = L(2-\sqrt{2})$ | A1 esc. | (5) |

## Part (b)

| Content | Marks | Notes |
|---------|-------|-------|
| $\dot{x} = -2L\omega\sin\omega t = -2L\frac{\pi}{3}\sin\frac{\pi}{6}$ | M1 | |
| Speed $= \frac{2L\pi}{3}$ | A1 | (2) |

## Part (c)

| Content | Marks | Notes |
|---------|-------|-------|
| $\frac{1}{2}(2-\sqrt{2})L = 2L\sin\omega t$ | M1 | |
| $t = 0.1467$ | A1 | |
| Total time $= 2 \times 0.1467 = 0.293$ (2 d.p.) | A1 | (3), (10) |

---
\begin{tikzpicture}[>=Stealth, thick]

  % Dimensions
  \def\L{10}      % total length (represents 4L)
  \def\H{1.4}     % bar height
  \def\b{3.0}     % width of inner rectangle (represents b)

  % Derived
  \pgfmathsetmacro{\px}{\L - \b}   % left edge of inner rect
  \pgfmathsetmacro{\qx}{\L}        % right edge of inner rect (flush with bar)

  % --- Filled bar (cyan) ---
  \fill[cyan!50] (0, 0) rectangle (\L, \H);

  % --- White inner rectangle (cutout region of width b) ---
  \fill[white] (\px, 0) rectangle (\qx, \H);
  \draw (\px, 0) rectangle (\qx, \H);

  % --- Outer bar outline ---
  \draw (0, 0) rectangle (\L, \H);

  % --- Dashed centre line A to B ---
  \draw[dashed] (0, {\H/2}) -- (\L, {\H/2});

  % --- Points A and B ---
  \node[left] at (0, {\H/2}) {$A$};
  \node[right] at (\L, {\H/2}) {$B$};

  % --- Points P, Q, C ---
  \node[above, yshift=1pt] at (\px, {\H/2}) {$P$};
  \node[above, yshift=1pt] at (\qx, {\H/2}) {$Q$};

  \pgfmathsetmacro{\cx}{0.5*(\px + \qx)}
  \fill (\cx, {\H/2}) circle (2pt);
  \node[below, yshift=-1pt] at (\cx, {\H/2}) {$C$};

  % --- Dimension: b (above the bar) ---
  \draw[<->] (\px, {\H + 0.5}) -- node[above] {$b$} (\qx, {\H + 0.5});
  \draw (\px, \H) -- (\px, {\H + 0.6});
  \draw (\qx, \H) -- (\qx, {\H + 0.6});

  % --- Dimension: 4L (below the bar) ---
  \draw[<->] (0, -0.5) -- node[below] {$4L$} (\L, -0.5);
  \draw (0, 0) -- (0, -0.6);
  \draw (\L, 0) -- (\L, -0.6);

\end{tikzpicture}

In a game at a fair, a small target $C$ moves horizontally with simple harmonic motion between the points $A$ and $B$, where $AB = 4L$. The target moves inside a box and takes 3 s to travel from $A$ to $B$. A player has to shoot at $C$, but $C$ is only visible to the player when it passes a window $PQ$, where $PQ = b$. The window is initially placed with $Q$ at the point as shown in Figure 4. The target $C$ takes 0.75 s to pass from $Q$ to $P$.

\begin{enumerate}[label=(\alph*)]
\item Show that $b = (2 - \sqrt{2})L$. [5]
\item Find the speed of $C$ as it passes $P$. [2]
\end{enumerate}

\includegraphics{figure_5}

For advanced players, the window $PQ$ is moved to the centre of $AB$ so that $AP = QB$, as shown in Figure 5.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{2}
\item Find the time, in seconds to 2 decimal places, taken for $C$ to pass from $Q$ to $P$ in this new position. [3]
\end{enumerate}

\hfill \mbox{\textit{Edexcel M3 2005 Q4 [10]}}