Edexcel M2 2013 June — Question 1 8 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Year2013
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCentre of Mass 1
TypeParticles at coordinate positions
DifficultyModerate -0.3 This is a straightforward application of the centre of mass formula with two unknowns. Students must set up and solve two linear equations using the standard formula (sum of mass×position)/(total mass) = centre of mass coordinate. While it requires careful algebraic manipulation across two parts, it's a routine textbook exercise with no conceptual challenges beyond direct formula application, making it slightly easier than average.
Spec6.04b Find centre of mass: using symmetry

Three particles of masses 2 kg, 3 kg and \(m\) kg are positioned at the points with coordinates \((a, 3)\), \((3, -1)\) and \((-2, 4)\) respectively. Given that the centre of mass of the particles is at the point with coordinates \((0, 2)\), find
  1. the value of \(m\), [4]
  2. the value of \(a\). [4]

(a)
AnswerMarks Guidance
\(6 - 3 + 4m = (m+5) \times 2\)M1 Moments equation for y coordinate. Terms of correct structure but condone sign slips
\(7 = 2m\)A2 -1 each error
\(m = 3.5\)A1(4)
(b)
AnswerMarks Guidance
\(2a + 9 - 2m = 0 (x(m+5))\)M1 Moments equation for x coordinate. Terms of correct structure but condone sign slips
A1
\(2a + 9 - 7 = 0\)M1 Substitute their m and solve for a
use their \(m\)
\(a = -1\)A1(4)
[8]
**(a)**

| $6 - 3 + 4m = (m+5) \times 2$ | M1 | Moments equation for y coordinate. Terms of correct structure but condone sign slips |
| $7 = 2m$ | A2 | -1 each error |
| $m = 3.5$ | A1(4) | |

**(b)**

| $2a + 9 - 2m = 0 (x(m+5))$ | M1 | Moments equation for x coordinate. Terms of correct structure but condone sign slips |
| | A1 | |
| $2a + 9 - 7 = 0$ | M1 | Substitute their m and solve for a |
| use their $m$ | | |
| $a = -1$ | A1(4) | |
| | [8] | |
Three particles of masses 2 kg, 3 kg and $m$ kg are positioned at the points with coordinates $(a, 3)$, $(3, -1)$ and $(-2, 4)$ respectively. Given that the centre of mass of the particles is at the point with coordinates $(0, 2)$, find

\begin{enumerate}[label=(\alph*)]
\item the value of $m$, [4]
\item the value of $a$. [4]
\end{enumerate}

\hfill \mbox{\textit{Edexcel M2 2013 Q1 [8]}}