Edexcel M2 2013 June — Question 2 6 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Year2013
SessionJune
Marks6
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Mark schemeDownload PDF ↗
TopicWork done and energy
TypeProjectile energy - basic KE/PE calculation
DifficultyStandard +0.3 This is a straightforward application of the work-energy principle to a vertical motion problem with constant resistance. Students must identify forces (weight and resistance both oppose motion upward), calculate work done by each force, and apply the work-energy equation. While it requires careful attention to signs and multiple steps, it's a standard M2 exercise with no conceptual surprises—slightly easier than average due to the direct application of a named principle with given values.
Spec6.02i Conservation of energy: mechanical energy principle
A ball of mass 0.2 kg is projected vertically upwards from a point \(O\) with speed 20 m s\(^{-1}\). The non-gravitational resistance acting on the ball is modelled as a force of constant magnitude 1.24 N and the ball is modelled as a particle. Find, using the work-energy principle, the speed of the ball when it first reaches the point which is 8 m vertically above \(O\). [6]
NB This question tells candidates to use work-energy - suvat approach scores 0/6
AnswerMarks Guidance
\(1.24 \times 8; \quad 0.2g \times 8; \quad \frac{1}{2}0.2 \cdot 20^2\) or \(\frac{1}{2}0.2v^2\)B1:B1:B1 B1 for each term seen or implied 9.92, 15.68, 40 or \(0.1v^2\)
\(1.24 \times 8 = \frac{1}{2}0.2 \cdot 20^2 - \frac{1}{2}0.2v^2 - 0.2g \times 8\)M1 Condone sign errors but all terms should be present
A1Correct equation
\(v = 12\)A1
(6)
[6] 
NB This question tells candidates to use work-energy - suvat approach scores 0/6

| $1.24 \times 8; \quad 0.2g \times 8; \quad \frac{1}{2}0.2 \cdot 20^2$ or $\frac{1}{2}0.2v^2$ | B1:B1:B1 | B1 for each term seen or implied 9.92, 15.68, 40 or $0.1v^2$ |
| $1.24 \times 8 = \frac{1}{2}0.2 \cdot 20^2 - \frac{1}{2}0.2v^2 - 0.2g \times 8$ | M1 | Condone sign errors but all terms should be present |
| | A1 | Correct equation |
| $v = 12$ | A1 | |
| | (6) |
| | [6] | |

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A ball of mass 0.2 kg is projected vertically upwards from a point $O$ with speed 20 m s$^{-1}$. The non-gravitational resistance acting on the ball is modelled as a force of constant magnitude 1.24 N and the ball is modelled as a particle. Find, using the work-energy principle, the speed of the ball when it first reaches the point which is 8 m vertically above $O$. [6]

\hfill \mbox{\textit{Edexcel M2 2013 Q2 [6]}}
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Q1 7 Q2 6 Q3 9 Q4 11 Q5 13 Q6 13 Q7 16