| Exam Board | Edexcel |
|---|---|
| Module | M2 (Mechanics 2) |
| Year | 2010 |
| Session | June |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Projectiles |
| Type | Projection from elevated point - angle above horizontal |
| Difficulty | Standard +0.3 This is a standard M2 projectiles question requiring routine application of SUVAT equations and projectile formulas. Part (a) uses the maximum height formula to find the angle, part (b) applies range formulas with the cliff height, and part (c) uses energy conservation or vertical motion equations. All techniques are textbook exercises with no novel problem-solving required, making it slightly easier than average. |
| Spec | 3.02d Constant acceleration: SUVAT formulae3.02i Projectile motion: constant acceleration model |
\includegraphics{figure_3}
A ball is projected with speed 40 m s$^{-1}$ from a point $P$ on a cliff above horizontal ground. The point $O$ on the ground is vertically below $P$ and $OP$ is 36 m. The ball is projected at an angle $\theta°$ to the horizontal. The point $Q$ is the highest point of the path of the ball and is 12 m above the level of $P$. The ball moves freely under gravity and hits the ground at the point $R$, as shown in Figure 3. Find
\begin{enumerate}[label=(\alph*)]
\item the value of $\theta$,
(3)
\item the distance $OR$,
(6)
\item the speed of the ball as it hits the ground at $R$.
(3)
\end{enumerate}
\hfill \mbox{\textit{Edexcel M2 2010 Q7}}