Standard +0.3 This is a standard M2 statics problem requiring three equilibrium equations (horizontal forces, vertical forces, and moments) with straightforward geometry. While it involves multiple steps and careful bookkeeping of forces, it follows a well-practiced template that M2 students drill extensively. The 'least coefficient' aspect is routine (friction at limiting equilibrium), and the given tan α simplifies trigonometry. Slightly easier than average due to its predictable structure.
\includegraphics{figure_1}
A uniform ladder \(AB\), of mass \(m\) and length \(2a\), has one end \(A\) on rough horizontal ground. The other end \(B\) rests against a smooth vertical wall. The ladder is in a vertical plane perpendicular to the wall. The ladder makes an angle \(\alpha\) with the horizontal, where \(\tan \alpha = \frac{4}{3}\). A child of mass \(2m\) stands on the ladder at \(C\) where \(AC = \frac{1}{2}a\), as shown in Fig. 1. The ladder and the child are in equilibrium.
By modelling the ladder as a rod and the child as a particle, calculate the least possible value of the coefficient of friction between the ladder and the ground. [9]
\includegraphics{figure_1}
A uniform ladder $AB$, of mass $m$ and length $2a$, has one end $A$ on rough horizontal ground. The other end $B$ rests against a smooth vertical wall. The ladder is in a vertical plane perpendicular to the wall. The ladder makes an angle $\alpha$ with the horizontal, where $\tan \alpha = \frac{4}{3}$. A child of mass $2m$ stands on the ladder at $C$ where $AC = \frac{1}{2}a$, as shown in Fig. 1. The ladder and the child are in equilibrium.
By modelling the ladder as a rod and the child as a particle, calculate the least possible value of the coefficient of friction between the ladder and the ground. [9]
\hfill \mbox{\textit{Edexcel M2 2003 Q3 [9]}}