Edexcel M2 2015 June — Question 7 13 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Year2015
SessionJune
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProjectiles
TypeVector form projectile motion
DifficultyStandard +0.3 This is a standard M2 projectiles question using vector notation. Part (a) is routine (vertical velocity = 0 at max height). Part (b) requires solving simultaneous equations from position components. Part (c) uses symmetry of parabolic motion. Part (d) requires finding when velocity is perpendicular to initial velocity using dot product. All techniques are standard M2 material with no novel insights required, making it slightly easier than average.
Spec3.02h Motion under gravity: vector form3.02i Projectile motion: constant acceleration model

[In this question, the unit vectors \(\mathbf{i}\) and \(\mathbf{j}\) are in a vertical plane, \(\mathbf{i}\) being horizontal and \(\mathbf{j}\) being vertically upwards.] At time \(t = 0\), a particle \(P\) is projected with velocity \((4\mathbf{i} + 9\mathbf{j})\) m s\(^{-1}\) from a fixed point \(O\) on horizontal ground. The particle moves freely under gravity. When \(P\) is at the point \(H\) on its path, \(P\) is at its greatest height above the ground.
  1. Find the time taken by \(P\) to reach \(H\). [2]
At the point \(A\) on its path, the position vector of \(P\) relative to \(O\) is \((k\mathbf{i} + k\mathbf{j})\) m, where \(k\) is a positive constant.
  1. Find the value of \(k\). [4]
  2. Find, in terms of \(k\), the position vector of the other point on the path of \(P\) which is at the same vertical height above the ground as the point \(A\). [3]
At time \(T\) seconds the particle is at the point \(B\) and is moving perpendicular to \((4\mathbf{i} + 9\mathbf{j})\)
  1. Find the value of \(T\). [4]

[In this question, the unit vectors $\mathbf{i}$ and $\mathbf{j}$ are in a vertical plane, $\mathbf{i}$ being horizontal and $\mathbf{j}$ being vertically upwards.]

At time $t = 0$, a particle $P$ is projected with velocity $(4\mathbf{i} + 9\mathbf{j})$ m s$^{-1}$ from a fixed point $O$ on horizontal ground. The particle moves freely under gravity. When $P$ is at the point $H$ on its path, $P$ is at its greatest height above the ground.

\begin{enumerate}[label=(\alph*)]
\item Find the time taken by $P$ to reach $H$. [2]
\end{enumerate}

At the point $A$ on its path, the position vector of $P$ relative to $O$ is $(k\mathbf{i} + k\mathbf{j})$ m, where $k$ is a positive constant.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item Find the value of $k$. [4]

\item Find, in terms of $k$, the position vector of the other point on the path of $P$ which is at the same vertical height above the ground as the point $A$. [3]
\end{enumerate}

At time $T$ seconds the particle is at the point $B$ and is moving perpendicular to $(4\mathbf{i} + 9\mathbf{j})$

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{3}
\item Find the value of $T$. [4]
\end{enumerate}

\hfill \mbox{\textit{Edexcel M2 2015 Q7 [13]}}