| Exam Board | Edexcel |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2003 |
| Session | November |
| Marks | 6 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | SUVAT in 2D & Gravity |
| Type | Vertical projection: speed of projection |
| Difficulty | Easy -1.2 This is a straightforward SUVAT application with vertical motion under gravity. Part (a) uses v²=u²+2as with v=0 at maximum height, and part (b) uses s=ut+½at² or symmetry. Both are standard textbook exercises requiring only direct formula substitution with no problem-solving insight or multi-step reasoning. |
| Spec | 3.02d Constant acceleration: SUVAT formulae3.02h Motion under gravity: vector form |
A small ball is projected vertically upwards from a point A. The greatest height reached by the ball is 40 m above A. Calculate
\begin{enumerate}[label=(\alph*)]
\item the speed of projection. [3]
\item the time between the instant that the ball is projected and the instant it returns to A. [3]
\end{enumerate}
\hfill \mbox{\textit{Edexcel M1 2003 Q1 [6]}}