| Exam Board | Edexcel |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2005 |
| Session | June |
| Marks | 8 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Motion on a slope |
| Type | Motion up rough slope |
| Difficulty | Moderate -0.3 This is a standard M1 mechanics problem requiring resolution of forces perpendicular and parallel to an inclined plane. Part (a) is straightforward application of equilibrium perpendicular to the plane. Part (b) requires calculating friction force and applying F=ma parallel to the plane. All values are given, making this slightly easier than average but still requiring proper method across 8 marks total. |
| Spec | 3.03a Force: vector nature and diagrams3.03b Newton's first law: equilibrium3.03c Newton's second law: F=ma one dimension3.03e Resolve forces: two dimensions3.03f Weight: W=mg3.03i Normal reaction force3.03r Friction: concept and vector form3.03t Coefficient of friction: F <= mu*R model3.03v Motion on rough surface: including inclined planes |
| Answer | Marks |
|---|---|
| 4 | R |
| Answer | Marks |
|---|---|
| Sub and solve: a = 0.123 or 0.12 m s–2 | M1 A1 |
Question 4:
4 | R
18
(a) R (perp to plane): R = 2g cos 20
≈ 18.4 or 18 N
F 2g
(b) R (// to plane): 18 – 2g sin 20 – F = 2a
F = 0.6 R used
Sub and solve: a = 0.123 or 0.12 m s–2 | M1 A1
A1
(3)
M1 A1
B1
↓
M1 A1
(5)\includegraphics{figure_2}
A box of mass 2 kg is pulled up a rough plane face by means of a light rope. The plane is inclined at an angle of $20°$ to the horizontal, as shown in Figure 2. The rope is parallel to a line of greatest slope of the plane. The tension in the rope is 18 N. The coefficient of friction between the box and the plane is 0.6. By modelling the box as a particle, find
\begin{enumerate}[label=(\alph*)]
\item the normal reaction of the plane on the box, [3]
\item the acceleration of the box. [5]
\end{enumerate}
\hfill \mbox{\textit{Edexcel M1 2005 Q4 [8]}}