Edexcel M1 2007 January — Question 3 9 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Year2007
SessionJanuary
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors Introduction & 2D
TypeNewton's second law with vector forces (find acceleration or force)
DifficultyModerate -0.8 This is a straightforward mechanics question requiring only direct application of standard formulas: (a) uses a = Δv/Δt, (b) applies F = ma and Pythagoras, (c) uses v = u + at. All steps are routine calculations with no problem-solving insight needed, making it easier than average but not trivial due to vector notation and multiple parts.
Spec1.10a Vectors in 2D: i,j notation and column vectors1.10b Vectors in 3D: i,j,k notation3.02e Two-dimensional constant acceleration: with vectors3.03c Newton's second law: F=ma one dimension3.03d Newton's second law: 2D vectors

A particle \(P\) of mass 2 kg is moving under the action of a constant force \(\mathbf{F}\) newtons. When \(t = 0\), \(P\) has velocity \((3\mathbf{i} + 2\mathbf{j})\) m s\(^{-1}\) and at time \(t = 4\) s, \(P\) has velocity \((15\mathbf{i} - 4\mathbf{j})\) m s\(^{-1}\). Find
  1. the acceleration of \(P\) in terms of \(\mathbf{i}\) and \(\mathbf{j}\), [2]
  2. the magnitude of \(\mathbf{F}\), [4]
  3. the velocity of \(P\) at time \(t = 6\) s. [3]

AnswerMarks Guidance
(a) \(a = \frac{(15i - 4j) - (3i + 2j)}{4} = 3i - 1.5j\)M1 A1 2 marks
(b) N2L: \(F = ma = 6i - 3j\)M1 A1 ft their \(a\)
(c) \(v_6 = (3i + 2j) + (3i - 1.5j) \times 6 = 21i - 7j\) (m s\(^{-1}\))M1 A1 ft their \(a\)
**(a)** $a = \frac{(15i - 4j) - (3i + 2j)}{4} = 3i - 1.5j$ | M1 A1 | 2 marks

**(b)** N2L: $F = ma = 6i - 3j$ | M1 A1 | ft their $a$ | $|F| = \sqrt{6^2 + 3^2} ≈ 6.71$ (N) | M1 A1 | accept $\sqrt{45}$, awrt 6.7 | 4 marks

**(c)** $v_6 = (3i + 2j) + (3i - 1.5j) \times 6 = 21i - 7j$ (m s$^{-1}$) | M1 A1 | ft their $a$ | 1 mark | 9 marks total

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A particle $P$ of mass 2 kg is moving under the action of a constant force $\mathbf{F}$ newtons. When $t = 0$, $P$ has velocity $(3\mathbf{i} + 2\mathbf{j})$ m s$^{-1}$ and at time $t = 4$ s, $P$ has velocity $(15\mathbf{i} - 4\mathbf{j})$ m s$^{-1}$. Find

\begin{enumerate}[label=(\alph*)]
\item the acceleration of $P$ in terms of $\mathbf{i}$ and $\mathbf{j}$, [2]
\item the magnitude of $\mathbf{F}$, [4]
\item the velocity of $P$ at time $t = 6$ s. [3]
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1 2007 Q3 [9]}}