Edexcel M1 2003 January — Question 3 6 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Year2003
SessionJanuary
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNewton's laws and connected particles
TypeSingle particle, Newton's second law – vector (2D forces)
DifficultyModerate -0.8 This is a straightforward application of constant acceleration kinematics and Newton's second law. Part (a) requires finding acceleration from change in velocity over time (a = Δv/Δt), and part (b) applies F = ma. Both are direct, single-step calculations with vector arithmetic that M1 students practice routinely. No problem-solving insight or multi-step reasoning required.
Spec1.10d Vector operations: addition and scalar multiplication3.03d Newton's second law: 2D vectors

A particle \(P\) of mass 0.4 kg is moving under the action of a constant force \(\mathbf{F}\) newtons. Initially the velocity of \(P\) is \((6\mathbf{i} - 2\mathbf{j})\) m s\(^{-1}\) and 4 s later the velocity of \(P\) is \((-14\mathbf{i} + 2\mathbf{j})\) m s\(^{-1}\).
  1. Find, in terms of \(\mathbf{i}\) and \(\mathbf{j}\), the acceleration of \(P\). [3]
  2. Calculate the magnitude of \(\mathbf{F}\). [3]

A particle $P$ of mass 0.4 kg is moving under the action of a constant force $\mathbf{F}$ newtons. Initially the velocity of $P$ is $(6\mathbf{i} - 2\mathbf{j})$ m s$^{-1}$ and 4 s later the velocity of $P$ is $(-14\mathbf{i} + 2\mathbf{j})$ m s$^{-1}$.

\begin{enumerate}[label=(\alph*)]
\item Find, in terms of $\mathbf{i}$ and $\mathbf{j}$, the acceleration of $P$. [3]
\item Calculate the magnitude of $\mathbf{F}$. [3]
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1 2003 Q3 [6]}}