Moderate -0.8 This is a straightforward kinematics question requiring only the constant velocity equation r = r₀ + vt. Students must work backwards to find position at t=0, then forward to t=2, and finally calculate distance using Pythagoras. All steps are routine with no conceptual challenges beyond basic vector arithmetic.
A particle \(P\) is moving with constant velocity \((-3\mathbf{i} + 2\mathbf{j})\) m s\(^{-1}\). At time \(t = 6\) s \(P\) is at the point with position vector \((-4\mathbf{i} - 7\mathbf{j})\) m. Find the distance of \(P\) from the origin at time \(t = 2\) s.
[5]
A particle $P$ is moving with constant velocity $(-3\mathbf{i} + 2\mathbf{j})$ m s$^{-1}$. At time $t = 6$ s $P$ is at the point with position vector $(-4\mathbf{i} - 7\mathbf{j})$ m. Find the distance of $P$ from the origin at time $t = 2$ s.
[5]
\hfill \mbox{\textit{Edexcel M1 Q1 [5]}}