Edexcel M1 2016 January — Question 7 16 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Year2016
SessionJanuary
Marks16
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPulley systems
TypeParticle on rough incline connected to particle on horizontal surface or other incline
DifficultyStandard +0.3 This is a standard M1 pulley system question with connected particles, requiring Newton's second law, friction calculations, and kinematics. While multi-part with several steps, it follows a predictable template: set up equations of motion for each particle, solve simultaneously for acceleration and tension, then apply SUVAT equations. The friction and inclined plane components are routine M1 topics. The final part requires careful application of equations of motion in two stages (before and after string breaks), which adds some complexity but remains within standard M1 problem-solving. Slightly easier than average due to its formulaic nature.
Spec3.02d Constant acceleration: SUVAT formulae3.03e Resolve forces: two dimensions3.03k Connected particles: pulleys and equilibrium3.03t Coefficient of friction: F <= mu*R model

\includegraphics{figure_3} A particle \(P\) of mass 2 kg is attached to one end of a light inextensible string. A particle \(Q\) of mass 5 kg is attached to the other end of the string. The string passes over a small smooth light pulley. The pulley is fixed at a point on the intersection of a rough horizontal table and a fixed smooth inclined plane. The string lies along the table and also lies in a vertical plane which contains a line of greatest slope of the inclined plane. This plane is inclined to the horizontal at an angle \(\alpha\), where \(\tan \alpha = \frac{3}{4}\). Particle \(P\) is at rest on the table, a distance \(d\) metres from the pulley. Particle \(Q\) is on the inclined plane with the string taut, as shown in Figure 3. The coefficient of friction between \(P\) and the table is \(\frac{1}{4}\). The system is released from rest and \(P\) slides along the table towards the pulley. Assuming that \(P\) has not reached the pulley and that \(Q\) remains on the inclined plane,
  1. write down an equation of motion for \(P\), [2]
  2. write down an equation of motion for \(Q\), [2]
    1. find the acceleration of \(P\),
    2. find the tension in the string. [5]
When \(P\) has moved a distance 0.5 m from its initial position, the string breaks. Given that \(P\) comes to rest just as it reaches the pulley,
  1. find the value of \(d\). [7]

Question 7:

AnswerMarks Guidance
7(a)T F2a M1 A1 (2)
(b)5gsinT 5a M1 A1 (2)
(c)R2g
F  1R
4
5g
a  3.5 ms2
14
AnswerMarks
T 11.9 N or12 NB1
B1
M1 A1
A1 (5)
AnswerMarks
(d)v2 2 x 3.5 x 0.5 = 3.5
() 0.5g2aa 0.25g (2.45)
03.52(2.45)s
s 5 (0.7142..)
7
d = 1  5  17 = 1.2 or 1.21
AnswerMarks
2 7 14M1 A1 ft
M1 A1
M1
A1
A1 ft (7)
16
Notes
AnswerMarks
7(a)M1 for N2L for P with correct no. of terms etc.
A1 for a correct equation
AnswerMarks
(b)M1 for N2L for Q with correct no. of terms etc.
A1 for a correct equation
(c)
(i)
AnswerMarks
(ii)First B1 for R = 2g
Second B1 for F = ¼ R seen, possibly on a diagram
First M1 for eliminating T or a and solving for T or a but must have had two
equations, each in T and a.
First A1 for 5g/14 or 3.5 or 7/2 (ms-2)
Second A1 for 17g/14 , 11.9 or 12 (N)
AnswerMarks
(d)First M1 for a complete method for finding v or v2 when the string breaks.
First A1 ft for a correct expression (may not be evaluated), ft on their accln
Second M1 for N2L for P
Second A1 for a correct value of a (may not be negative)
Third M1 (Must have found a deceleration using N2L and a value for v or v2) for a
complete method to find distance moved by P
Third A1 for a correct distance (s) cao.
Fourth A1 ft for (their s + 0.5)
N.B. For both third and fourth A marks, allow a fraction or any number of decimal
places, since g cancels.
PPMMTT
Pearson Education Limited. Registered company number 872828
with its registered office at 80 Strand, London, WC2R 0RL, United Kingdom
Question 7:
--- 7(a) ---
7(a) | T F2a | M1 A1 (2)
(b) | 5gsinT 5a | M1 A1 (2)
(c) | R2g
F  1R
4
5g
a  3.5 ms2
14
T 11.9 N or12 N | B1
B1
M1 A1
A1 (5)
(d) | v2 2 x 3.5 x 0.5 = 3.5
() 0.5g2aa 0.25g (2.45)
03.52(2.45)s
s 5 (0.7142..)
7
d = 1  5  17 = 1.2 or 1.21
2 7 14 | M1 A1 ft
M1 A1
M1
A1
A1 ft (7)
16
Notes
7(a) | M1 for N2L for P with correct no. of terms etc.
A1 for a correct equation
(b) | M1 for N2L for Q with correct no. of terms etc.
A1 for a correct equation
(c)
(i)
(ii) | First B1 for R = 2g
Second B1 for F = ¼ R seen, possibly on a diagram
First M1 for eliminating T or a and solving for T or a but must have had two
equations, each in T and a.
First A1 for 5g/14 or 3.5 or 7/2 (ms-2)
Second A1 for 17g/14 , 11.9 or 12 (N)
(d) | First M1 for a complete method for finding v or v2 when the string breaks.
First A1 ft for a correct expression (may not be evaluated), ft on their accln
Second M1 for N2L for P
Second A1 for a correct value of a (may not be negative)
Third M1 (Must have found a deceleration using N2L and a value for v or v2) for a
complete method to find distance moved by P
Third A1 for a correct distance (s) cao.
Fourth A1 ft for (their s + 0.5)
N.B. For both third and fourth A marks, allow a fraction or any number of decimal
places, since g cancels.
PPMMTT
Pearson Education Limited. Registered company number 872828
with its registered office at 80 Strand, London, WC2R 0RL, United Kingdom
\includegraphics{figure_3}

A particle $P$ of mass 2 kg is attached to one end of a light inextensible string. A particle $Q$ of mass 5 kg is attached to the other end of the string. The string passes over a small smooth light pulley. The pulley is fixed at a point on the intersection of a rough horizontal table and a fixed smooth inclined plane. The string lies along the table and also lies in a vertical plane which contains a line of greatest slope of the inclined plane. This plane is inclined to the horizontal at an angle $\alpha$, where $\tan \alpha = \frac{3}{4}$. Particle $P$ is at rest on the table, a distance $d$ metres from the pulley. Particle $Q$ is on the inclined plane with the string taut, as shown in Figure 3. The coefficient of friction between $P$ and the table is $\frac{1}{4}$.

The system is released from rest and $P$ slides along the table towards the pulley.

Assuming that $P$ has not reached the pulley and that $Q$ remains on the inclined plane,

\begin{enumerate}[label=(\alph*)]
\item write down an equation of motion for $P$, [2]

\item write down an equation of motion for $Q$, [2]

\item 
\begin{enumerate}[label=(\roman*)]
\item find the acceleration of $P$,
\item find the tension in the string. [5]
\end{enumerate}
\end{enumerate}

When $P$ has moved a distance 0.5 m from its initial position, the string breaks. Given that $P$ comes to rest just as it reaches the pulley,

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{3}
\item find the value of $d$. [7]
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1 2016 Q7 [16]}}