Edexcel C2 2008 January — Question 3 7 marks

Exam BoardEdexcel
ModuleC2 (Core Mathematics 2)
Year2008
SessionJanuary
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeNumerical approximation using expansion
DifficultyModerate -0.8 This is a straightforward binomial expansion question requiring direct application of the formula for the first four terms, followed by a routine substitution (x=0.01) to estimate a numerical value. Both parts are standard textbook exercises with no problem-solving or insight required, making it easier than average but not trivial since it involves multiple terms and careful arithmetic.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

  1. Find the first 4 terms of the expansion of \(\left(1 + \frac{x}{2}\right)^{10}\) in ascending powers of \(x\), giving each term in its simplest form. [4]
  2. Use your expansion to estimate the value of \((1.005)^{10}\), giving your answer to 5 decimal places. [3]

AnswerMarks
(a) \[\left(1 + \frac{1}{2}x\right)^{10} = 1 + \binom{10}{1}\left(\frac{1}{2}x\right) + \binom{10}{2}\left(\frac{1}{2}x\right)^2 + \binom{10}{3}\left(\frac{1}{2}x\right)^3\]M1 A1
\[= 1 + 5x + \frac{45}{4}(or\ 11.25)x^2 + 15x^3\] (coeffs need to be these, i.e., simplified)A1; A1 (4)
[Allow A1A0, if totally correct with unsimplified, single fraction coefficients]
Notes:
- (a) For M1 first A1: Consider underlined expression only.
- M1 Requires correct structure for at least two of the three terms:
- (i) Must be attempt at binomial coefficients.
- (ii) Must have increasing powers of \(x\).
- (iii) May be listed, need not be added; this applies for all marks.
- First A1: Requires all three correct terms but need not be simplified, allow \(1^{10}\) etc., \(^{10}C_r\) etc., and condone omission of brackets around powers of \(\frac{1}{2}x\)
- Second A1: Consider as B1 for \(1 + 5x\)
AnswerMarks
(b) \((1 + \frac{1}{2} \times 0.01)^{10} = 1 + 5(0.01) + \frac{45}{4}or11.25(0.01)^2 + 15(0.01)^3\)M1 A1 √
\[= 1 + 0.05 + 0.001125 + 0.000015\]
\[= 1.05114\] (cao)A1 (3) [7]
Notes:
- (b) For M1: Substituting their (0.01) into their (a) result
- First A1 (f.t.): Substitution of (0.01) into their 4-termed expression in (a)
- Answer with no working scores no marks (calculator gives this answer)
**(a)** $$\left(1 + \frac{1}{2}x\right)^{10} = 1 + \binom{10}{1}\left(\frac{1}{2}x\right) + \binom{10}{2}\left(\frac{1}{2}x\right)^2 + \binom{10}{3}\left(\frac{1}{2}x\right)^3$$ | M1 A1 |

$$= 1 + 5x + \frac{45}{4}(or\ 11.25)x^2 + 15x^3$$ (coeffs need to be these, i.e., simplified) | A1; A1 (4) |

[Allow A1A0, if totally correct with unsimplified, single fraction coefficients]

**Notes:**
- (a) For M1 first A1: Consider underlined expression only.
- M1 Requires correct structure for at least two of the three terms:
  - (i) Must be attempt at binomial coefficients.
  - (ii) Must have increasing powers of $x$.
  - (iii) May be listed, need not be added; this applies for all marks.
- First A1: Requires all three correct terms but need not be simplified, allow $1^{10}$ etc., $^{10}C_r$ etc., and condone omission of brackets around powers of $\frac{1}{2}x$
- Second A1: Consider as B1 for $1 + 5x$

**(b)** $(1 + \frac{1}{2} \times 0.01)^{10} = 1 + 5(0.01) + \frac{45}{4}or11.25(0.01)^2 + 15(0.01)^3$ | M1 A1 √ |
$$= 1 + 0.05 + 0.001125 + 0.000015$$ | |
$$= 1.05114$$ (cao) | A1 (3) [7] |

**Notes:**
- (b) For M1: Substituting their (0.01) into their (a) result
- First A1 (f.t.): Substitution of (0.01) into their 4-termed expression in (a)
- Answer with no working scores no marks (calculator gives this answer)

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\begin{enumerate}[label=(\alph*)]
\item Find the first 4 terms of the expansion of $\left(1 + \frac{x}{2}\right)^{10}$ in ascending powers of $x$, giving each term in its simplest form. [4]

\item Use your expansion to estimate the value of $(1.005)^{10}$, giving your answer to 5 decimal places. [3]
\end{enumerate}

\hfill \mbox{\textit{Edexcel C2 2008 Q3 [7]}}