Edexcel C2 — Question 6 7 marks

Exam BoardEdexcel
ModuleC2 (Core Mathematics 2)
Marks7
PaperDownload PDF ↗
TopicSine and Cosine Rules
TypeBearings and navigation
DifficultyModerate -0.3 This is a straightforward application of the cosine rule followed by the sine rule in a bearings context. Part (a) requires recognizing the angle at A is 75° (90° - 15°) and applying the cosine rule directly. Part (b) uses the sine rule to find an angle, then converts to a bearing. While it requires careful angle work with bearings, it's a standard two-part question with no novel problem-solving, making it slightly easier than average.
Spec1.05b Sine and cosine rules: including ambiguous case

\includegraphics{figure_1} Figure 1 shows 3 yachts \(A\), \(B\) and \(C\) which are assumed to be in the same horizontal plane. Yacht \(B\) is 500 m due north of yacht \(A\) and yacht \(C\) is 700 m from \(A\). The bearing of \(C\) from \(A\) is 015°.
  1. Calculate the distance between yacht \(B\) and yacht \(C\), in metres to 3 significant figures. [3]
The bearing of yacht \(C\) from yacht \(B\) is \(\theta°\), as shown in Figure 1.
  1. Calculate the value of \(\theta\). [4]

\includegraphics{figure_1}

Figure 1 shows 3 yachts $A$, $B$ and $C$ which are assumed to be in the same horizontal plane. Yacht $B$ is 500 m due north of yacht $A$ and yacht $C$ is 700 m from $A$. The bearing of $C$ from $A$ is 015°.

\begin{enumerate}[label=(\alph*)]
\item Calculate the distance between yacht $B$ and yacht $C$, in metres to 3 significant figures.
[3]
\end{enumerate}

The bearing of yacht $C$ from yacht $B$ is $\theta°$, as shown in Figure 1.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item Calculate the value of $\theta$.
[4]
\end{enumerate}

\hfill \mbox{\textit{Edexcel C2  Q6 [7]}}