| Exam Board | Edexcel |
|---|---|
| Module | P1 (Pure Mathematics 1) |
| Year | 2018 |
| Session | Specimen |
| Marks | 12 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Sine and Cosine Rules |
| Type | Shaded region with arc |
| Difficulty | Moderate -0.3 This is a straightforward multi-part question testing standard applications of cosine rule, sector area, and triangle area formulas. Part (a) is routine cosine rule calculation, parts (b-d) involve standard sector and triangle area computations with clear given values. While it requires multiple steps (12 marks total), each individual step uses direct formula application without requiring problem-solving insight or novel approaches, making it slightly easier than average. |
| Spec | 1.05b Sine and cosine rules: including ambiguous case1.05d Radians: arc length s=r*theta and sector area A=1/2 r^2 theta |
| Answer | Marks |
|---|---|
| 10(a) | Correct use of cosine rule |
| Answer | Marks |
|---|---|
| 2(cid:117)4(cid:117)6 (cid:169) 48 (cid:185) | M1 |
| (cid:68) = 2.22 (cid:13) cso | A1 |
| Answer | Marks |
|---|---|
| XY2 (cid:32)42 (cid:14)62 (cid:16)2(cid:117)4(cid:117)6cos2.22(cid:159) XY2 (cid:32).. | Correct use of cosine rule |
| leading to a value for XY2 | M1 |
| XY = 9.00.... | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| (b) | 2(cid:83)(cid:16)2.22((cid:32)4.06366......) | 2(cid:83)(cid:16)2.22 or 2(cid:83)(cid:16)2.2or awrt |
| 4.06 (May be implied) | B1 |
| Answer | Marks |
|---|---|
| 2 | Correct method for major |
| Answer | Marks | Guidance |
|---|---|---|
| for the major sector angle. | M1 | |
| 32.5 | Awrt 32.5 | A1 |
| Answer | Marks |
|---|---|
| (cid:83)(cid:117)42 | Correct expression for circle |
| area | B1 |
| Answer | Marks | Guidance |
|---|---|---|
| 2 | Correct method for | |
| circle - minor sector area | M1 | |
| (cid:32)32.5 | Awrt 32.5 | A1 |
| Answer | Marks |
|---|---|
| (c) | Area of triangle = |
| Answer | Marks |
|---|---|
| 2 | Correct expression for the area of |
| Answer | Marks |
|---|---|
| 2.22) | B1 |
| So area required = “9.56” + “32.5” | Their Triangle XYZ + part (b) or |
| Answer | Marks | Guidance |
|---|---|---|
| (Not triangle ZXW) | M1 | |
| Area of logo = 42.1 cm2 or 42.0 cm2 | Awrt 42.1 or 42.0 (or just 42) | A1 |
| Answer | Marks |
|---|---|
| (d) | Arc length(cid:32)4(cid:117)4.06(cid:11)(cid:32)16.24(cid:12) |
| Answer | Marks |
|---|---|
| 8(cid:83)(cid:16)4(cid:117)2.22 | M1: 4(cid:117)their(cid:11)2(cid:83)(cid:16)2.22(cid:12) |
| Answer | Marks |
|---|---|
| A1: Correct ft expression | M1 |
| Answer | Marks | Guidance |
|---|---|---|
| Perimeter = ZY + WY + Arc Length | 9 + 2 + Any Arc | M1 |
| Perimeter of logo = 27.2 or 27.3 | Awrt 27.2 or awrt 27.3 | A1 |
Question 10:
--- 10(a) ---
10(a) | Correct use of cosine rule
92 (cid:32)42 (cid:14)62 (cid:16)2(cid:117)4(cid:117)6cos(cid:68)(cid:159)cos(cid:68)(cid:32).....
leading to a value for cos (cid:68)
42 (cid:14)62 (cid:16)92 (cid:167) 29 (cid:183)
cos(cid:68)(cid:32) (cid:168)(cid:32)(cid:16) (cid:32)(cid:16)0.604..(cid:184)
2(cid:117)4(cid:117)6 (cid:169) 48 (cid:185) | M1
(cid:68) = 2.22 (cid:13) cso | A1
(2)
Alternative
XY2 (cid:32)42 (cid:14)62 (cid:16)2(cid:117)4(cid:117)6cos2.22(cid:159) XY2 (cid:32).. | Correct use of cosine rule
leading to a value for XY2 | M1
XY = 9.00.... | A1
(2)
(b) | 2(cid:83)(cid:16)2.22((cid:32)4.06366......) | 2(cid:83)(cid:16)2.22 or 2(cid:83)(cid:16)2.2or awrt
4.06 (May be implied) | B1
1(cid:117)42(cid:117)"4.06"
2 | Correct method for major
sector area. Allow (cid:83)(cid:16)2.22
for the major sector angle. | M1
32.5 | Awrt 32.5 | A1
(3)
Alternative – Circle Minor – sector
(cid:83)(cid:117)42 | Correct expression for circle
area | B1
1
(cid:83)(cid:117)42 (cid:16) (cid:117)42 (cid:117)2.22(cid:32)32.5
2 | Correct method for
circle - minor sector area | M1
(cid:32)32.5 | Awrt 32.5 | A1
(3)
(c) | Area of triangle =
1
(cid:117)4(cid:117)6(cid:117)sin2.22(cid:11)(cid:32)9.56(cid:12)
2 | Correct expression for the area of
triangle XYZ (allow 2.2 or awrt
2.22) | B1
So area required = “9.56” + “32.5” | Their Triangle XYZ + part (b) or
correct attempt at major sector
(Not triangle ZXW) | M1
Area of logo = 42.1 cm2 or 42.0 cm2 | Awrt 42.1 or 42.0 (or just 42) | A1
(3)
(d) | Arc length(cid:32)4(cid:117)4.06(cid:11)(cid:32)16.24(cid:12)
or
8(cid:83)(cid:16)4(cid:117)2.22 | M1: 4(cid:117)their(cid:11)2(cid:83)(cid:16)2.22(cid:12)
or circumference – minor arc
A1: Correct ft expression | M1
A1ft
Perimeter = ZY + WY + Arc Length | 9 + 2 + Any Arc | M1
Perimeter of logo = 27.2 or 27.3 | Awrt 27.2 or awrt 27.3 | A1
(4)
(12 marks)
PPPMMMTTT
44 Pearson Edexcel International Advanced Subsidiary/Advanced Level in Mathematics, Further Mathematics and
Pure Mathematics – Sample Assessment Materials (SAMs) – Issue 3 – June 2018 © Pearson Education Limited 2018
\includegraphics{figure_4}
The triangle $XYZ$ in Figure 4 has $XY = 6$ cm, $YZ = 9$ cm, $ZX = 4$ cm and angle $ZXY = a$.
The point $W$ lies on the line $XY$.
The circular arc $ZW$, in Figure 4, is a major arc of the circle with centre $X$ and radius 4 cm.
\begin{enumerate}[label=(\alph*)]
\item Show that, to 3 significant figures, $a = 2.22$ radians. [2]
\item Find the area, in cm$^2$, of the major sector $XZWX$. [3]
\end{enumerate}
The region, shown shaded in Figure 4, is to be used as a design for a logo.
Calculate
\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{2}
\item the area of the logo [3]
\item the perimeter of the logo. [4]
\end{enumerate}
\hfill \mbox{\textit{Edexcel P1 2018 Q10 [12]}}