CAIE P1 2008 June — Question 1 3 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2008
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSine and Cosine Rules
TypeExact trigonometric values
DifficultyModerate -0.5 This is a straightforward application of the sine rule to find one side given two angles and one side. The angles are special angles (45° and 60°) allowing exact values, but the calculation is routine with no problem-solving required beyond recognizing which rule to apply.
Spec1.05b Sine and cosine rules: including ambiguous case1.05g Exact trigonometric values: for standard angles

1 In the triangle \(A B C , A B = 12 \mathrm {~cm}\), angle \(B A C = 60 ^ { \circ }\) and angle \(A C B = 45 ^ { \circ }\). Find the exact length of \(B C\).

AnswerMarks Guidance
Use of sine rule \(\frac{12}{\sin 45} = \frac{x}{\sin 60}\)M1 Used correctly in their triangle \(ABC\)
\(\sin 60 = \frac{\sqrt{3}}{2}\) and \(\sin 45 = \frac{1}{\sqrt{2}}\)B1 Both of these correct
\(\rightarrow BC = 6\sqrt{3}\sqrt{2}\) or \(6\sqrt{6}\) or \(\sqrt{216}\)A1 Co – must be in surd form. [3]
Use of sine rule $\frac{12}{\sin 45} = \frac{x}{\sin 60}$ | M1 | Used correctly in their triangle $ABC$

$\sin 60 = \frac{\sqrt{3}}{2}$ and $\sin 45 = \frac{1}{\sqrt{2}}$ | B1 | Both of these correct

$\rightarrow BC = 6\sqrt{3}\sqrt{2}$ or $6\sqrt{6}$ or $\sqrt{216}$ | A1 | Co – must be in surd form. [3]
1 In the triangle $A B C , A B = 12 \mathrm {~cm}$, angle $B A C = 60 ^ { \circ }$ and angle $A C B = 45 ^ { \circ }$. Find the exact length of $B C$.

\hfill \mbox{\textit{CAIE P1 2008 Q1 [3]}}