\begin{tikzpicture}[thick, scale=1, every node/.style={font=\small}]

  % First split
  \draw (0,0) -- node[above, sloped] {0.3} (4,1.8);
  \draw (0,0) -- (4,-1.8);

  % First level labels
  \node[right] at (4,1.8) {Nikita buys a scarf};
  \node[right] at (4,-1.8) {Nikita buys a handbag};

  % Second split from "scarf"
  \draw (6.8,1.8) -- node[above, sloped] {0.72} (10,3);
  \draw (6.8,1.8) -- (10,0.6);

  % Second level labels (scarf)
  \node[right] at (10,3) {Mother likes her present};
  \node[right] at (10,0.6) {Mother does not like her present};

  % Second split from "handbag"
  \draw (7.4,-1.8) -- node[above, sloped] {$x$} (10,-0.6);
  \draw (7.4,-1.8) -- (10,-3);

  % Second level labels (handbag)
  \node[right] at (10,-0.6) {Mother likes her present};
  \node[right] at (10,-3) {Mother does not like her present};

\end{tikzpicture}

Nikita goes shopping to buy a birthday present for her mother. She buys either a scarf, with probability 0.3, or a handbag. The probability that her mother will like the choice of scarf is 0.72. The probability that her mother will like the choice of handbag is $x$. This information is shown on the tree diagram. The probability that Nikita's mother likes the present that Nikita buys is 0.783.

\begin{enumerate}[label=(\roman*)]
\item Find $x$. [3]
\item Given that Nikita's mother does not like her present, find the probability that the present is a scarf. [4]
\end{enumerate}

\hfill \mbox{\textit{CAIE S1 2015 Q4 [7]}}