CAIE Further Paper 3 2024 November — Question 1 3 marks

Exam BoardCAIE
ModuleFurther Paper 3 (Further Paper 3)
Year2024
SessionNovember
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircular Motion 1
TypeElastic string – horizontal circle on surface
DifficultyStandard +0.3 This is a straightforward circular motion problem requiring application of Hooke's law and centripetal force equation. With only 3 marks, it involves setting T = λx/l equal to mrω², then solving for x - a standard exercise with no conceptual difficulty beyond knowing the basic formulas.
Spec6.05c Horizontal circles: conical pendulum, banked tracks

A particle of mass \(2\) kg is attached to one end of a light elastic string of natural length \(0.8\) m and modulus of elasticity \(100\) N. The other end of the string is attached to a fixed point \(O\) on a smooth horizontal surface. The particle is moving in a horizontal circle about \(O\) with the string taut and with constant angular speed \(5\) radians per second. Find the extension of the string. [3]

Question 1:
AnswerMarks
1100
Hooke’s law: T = x
AnswerMarks Guidance
0.8B1 100
T = (r−0.8)
0.8
AnswerMarks Guidance
N2L: T =2(0.8+x)52B1 T =2r52
Equate and solve: 50(0.8+x)=125x, x=0.533B1 8
15
3
AnswerMarks Guidance
QuestionAnswer Marks
Question 1:
1 | 100
Hooke’s law: T = x
0.8 | B1 | 100
T = (r−0.8)
0.8
N2L: T =2(0.8+x)52 | B1 | T =2r52
Equate and solve: 50(0.8+x)=125x, x=0.533 | B1 | 8
15
3
Question | Answer | Marks | Guidance
A particle of mass $2$ kg is attached to one end of a light elastic string of natural length $0.8$ m and modulus of elasticity $100$ N. The other end of the string is attached to a fixed point $O$ on a smooth horizontal surface. The particle is moving in a horizontal circle about $O$ with the string taut and with constant angular speed $5$ radians per second.

Find the extension of the string. [3]

\hfill \mbox{\textit{CAIE Further Paper 3 2024 Q1 [3]}}