CAIE Further Paper 3 2024 November — Question 6 3 marks

Exam BoardCAIE
ModuleFurther Paper 3 (Further Paper 3)
Year2024
SessionNovember
Marks3
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Mark schemeDownload PDF ↗
TopicCircular Motion 1
TypeConical pendulum – horizontal circle in free space (no surface)
DifficultyModerate -0.5 This is part (b) of a multi-part circular motion question worth 3 marks. Finding angular velocity ω typically involves applying standard circular motion formulas (v=rω or centripetal force equations) with given values. While it's a Further Maths topic, this appears to be a straightforward calculation step rather than requiring conceptual insight or extended reasoning, making it slightly easier than average.
Spec6.05c Horizontal circles: conical pendulum, banked tracks
  1. Find the value of \(\omega\). [3]
Question 6:
AnswerMarks
6(a)At P:  T cos=T cos+0.05g
1 2
At Q:  T cos=0.04g
AnswerMarks
2B1
B1OR: whole system: T cos=0.09g
1
T =0.15g =1.5 N
AnswerMarks
1B1
3
AnswerMarks
6(b)T sin−T sin=0.050.82
1 2
T sin=0.041.42
AnswerMarks Guidance
2M1 Allow sin/cos mix
M1
T sin=0.050.82 +0.041.42
1
5
2 =12.5,  = 2
AnswerMarks
2A1
3
AnswerMarks
6(c)T cos=0.04g and T sin=0.041.42
2 2
7
Divide: tan=
AnswerMarks Guidance
4M1 From part (a) and part (b)
=60.3A1
2
AnswerMarks Guidance
QuestionAnswer Marks 
Question 6:
--- 6(a) ---
6(a) | At P:  T cos=T cos+0.05g
1 2
At Q:  T cos=0.04g
2 | B1
B1 | OR: whole system: T cos=0.09g
1
T =0.15g =1.5 N
1 | B1
3
--- 6(b) ---
6(b) | T sin−T sin=0.050.82
1 2
T sin=0.041.42
2 | M1 | Allow sin/cos mix
M1
T sin=0.050.82 +0.041.42
1
5
2 =12.5,  = 2
2 | A1
3
--- 6(c) ---
6(c) | T cos=0.04g and T sin=0.041.42
2 2
7
Divide: tan=
4 | M1 | From part (a) and part (b)
=60.3 | A1
2
Question | Answer | Marks | Guidance
\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item Find the value of $\omega$. [3]
\end{enumerate}

\hfill \mbox{\textit{CAIE Further Paper 3 2024 Q6 [3]}}
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Q1 5 Q2 5 Q3 6 Q3 2 Q4 4 Q4 3 Q5 4 Q5 3 Q6 3 Q6 3 Q6 2 Q7 4 Q7 6