CAIE M2 2014 November — Question 4 8 marks

Exam BoardCAIE
ModuleM2 (Mechanics 2)
Year2014
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCentre of Mass 1
TypeComposite solid with hemisphere and cylinder/cone
DifficultyStandard +0.3 This is a standard centre of mass problem requiring application of standard formulas for cylinder and hemisphere centres of mass, followed by a routine equilibrium condition. The composite centre of mass calculation is straightforward (5 marks), and the tilting equilibrium condition (tan α = base radius / height to COM) is a direct application of a standard result (3 marks). Slightly above average difficulty due to 3D geometry and two-part structure, but all techniques are standard textbook exercises.
Spec6.04c Composite bodies: centre of mass6.04e Rigid body equilibrium: coplanar forces

\includegraphics{figure_4} The diagram shows the cross-section of a uniform solid consisting of a cylinder of radius \(0.4\) m and height \(1.5\) m with a hemisphere of radius \(0.4\) m on top.
  1. Find the distance of the centre of mass above the base of the cylinder. [5]
  2. The solid can just rest in equilibrium on a plane inclined at angle \(\alpha\) to the horizontal. Find \(\alpha\). [3]

Question 4:

(ii) ---
4 (i)
AnswerMarks
(ii)ABCF area = 0.64 and CDE = 0.36
0.4 1.8
(0.64 + 0.36)d = 0.64× + 0.36×(0.4 + )
2 3
d = 0.488 m AG
0.488 × 100 = 1.6T
T = 30.5 N
(0.488 – 0.4) × 100 = 1.6T
AnswerMarks
T = 5.5B1
M1
A1
A1
[4]
M1
A1
AnswerMarks
A1 [3]Both areas correct
Table of moments idea
All terms correct
Either limiting case
(no turning about A)
(no turning about F)
AnswerMarks Guidance
Page 5Mark Scheme Syllabus
Cambridge International A Level – October/November 20149709 51
Question 4:
--- 4 (i)
(ii) ---
4 (i)
(ii) | ABCF area = 0.64 and CDE = 0.36
0.4 1.8
(0.64 + 0.36)d = 0.64× + 0.36×(0.4 + )
2 3
d = 0.488 m AG
0.488 × 100 = 1.6T
T = 30.5 N
(0.488 – 0.4) × 100 = 1.6T
T = 5.5 | B1
M1
A1
A1
[4]
M1
A1
A1 [3] | Both areas correct
Table of moments idea
All terms correct
Either limiting case
(no turning about A)
(no turning about F)
Page 5 | Mark Scheme | Syllabus | Paper
Cambridge International A Level – October/November 2014 | 9709 | 51
\includegraphics{figure_4}

The diagram shows the cross-section of a uniform solid consisting of a cylinder of radius $0.4$ m and height $1.5$ m with a hemisphere of radius $0.4$ m on top.

\begin{enumerate}[label=(\roman*)]
\item Find the distance of the centre of mass above the base of the cylinder. [5]
\item The solid can just rest in equilibrium on a plane inclined at angle $\alpha$ to the horizontal. Find $\alpha$. [3]
\end{enumerate}

\hfill \mbox{\textit{CAIE M2 2014 Q4 [8]}}